解析时间军事时间字符串的特殊情况

Question

usually, most military times are like this

12:34:56

I already figured an method to extract the Hours,mins and secs into their own strings.

However, there is a corner case that i can't seem to figure out

example:

12::

after extracting the number and converting to integers, result is 0. That is good. However, i need two 0's to properly represent the time

char *hh = argv[2];
char *mm, *ss;
char *array[3];
char *temp =strchr(argv[2],':');
mm = temp + 1;

/*if(*mm == ':'){

  *mm = "00";
}*/

*temp = '\0';
temp = strchr(mm, ':');
ss = temp+1;
*temp = '\0';

if you look at the commented if part, that is my attempt to check if the next pointed value is a semicolon. If it is, all i need to do is it with two 0's.

Any clue how to deal with this?

Answer 1

It would be much better to extract this data as integers, not strings.

Something like:

bool parse_hms(int *hours, int *minutes, int *seconds, const char *hms)
{
  *hours = *minutes = *seconds = 0;

  return sscanf(hms, "%d:%d:%d", hours, minutes, seconds) > 0;
}

should work. Note that the function assumes that all three pointers are valid. It returns true if at least one of the numbers was parsed out. Non-parsed numbers will be set to 0 (which of course is also valid as an element value).