试图将ajax请求放入另一个ajax请求的成功回调中

Question

I am trying to make two jQuery ajax calls, the second should be made from the success callback of the first. I have tried a couple variations of code eg just messing with the brackets.

Here is what I tried.

$.ajax({
    url: 'inc/grab_talk.php?name='+encoded_name+'&loc='+encoded_address+'&lat='+encoded_lat,
    type: 'post',
    success: function () {

        $.ajax({
            url: 'inc/talk_results.php',
            type: 'post',
            success: function (dat) {
                alert(dat);
            }
        });

    }
});

I am receiving '500 (internal server error) in console

Answer 1

Try this, you can use either POST or GET, but in your case GET seems to be more appropriate.

$.ajax({
  type: "GET",
  url: "some.php",
  data: { name: "somename", location: "somelocation" },
  success: function(){
      $.ajax({
        type: "GET",
        url: "someother.php",
        success: function(){
            alert('test');
        }
      });
    }
});

Answer 2

Check this example

$.ajax({
        type: "post",
        url: "ajax/example.php",
        data: 'page='+btn_page,
        success: function(data){
            $.ajax({
                var a=data; //edit data here
                type: "post",
                url: "example.php",
                data: 'page='+a,
                success: function(data){

});
});