[英]Passing XML data to SOAP service dilemma
I had posted this question yesterday: How to go about creating SOAP webservice in Java and after following this book: http://www.packtpub.com/java-7-jax-ws-web-services/book I have managed to created a JAX-WS application: 我昨天发布了这个问题:在遵循本书之后, 如何用Java创建SOAP Web服务 : http : //www.packtpub.com/java-7-jax-ws-web-services/book我设法创建了JAX-WS应用程序:
package hellows;
import javax.jws.*;
@WebService(portName = "HelloWSPort", serviceName = "HelloWSService", targetNamespace = "http://hellows/", endpointInterface = "hellows.HelloWS")
public class HelloWSImpl implements HelloWS {
public String hello(String name) {
// replace with your impl here
return "Hello "+name +" Welcome to Web Services!";
}
}
All is fine. 一切都很好。 But what I need is that the service method(ie "hello") should instead of "string" accept an XML file describing student details(I've changed the original file):
但是我需要的是服务方法(即“ hello”)应该代替“ string”接受描述学生详细信息的XML文件(我已经更改了原始文件):
<?STU version="1.0"?>
<stu>
<id sequence="1">2354282</id>
<date>2012-06-17T21:19:15</date>
<student interest="food" status="newadmission">
<id></id>
<birthyear>2012</birthyear>
<sex>Male</sex>
<address>Sonata</address>
<class>3</class>
</student>
</stu>
Then the service will process it and return a Java Object containing a flag "passed"/"failed" based on some algo. 然后,该服务将对其进行处理,并根据某种算法返回一个包含标志“通过” /“失败”的Java对象。
So my question is: 所以我的问题是:
I have done a similar thing using AXIS2. 我已经使用AXIS2做过类似的事情。 So, my answer might be able to give you some hope :)
因此,我的回答可能会给您一些希望:)
In services.xml file: Configure your hello
operation in such a way that its messageReceiver
class is of type org.apache.axis2.receivers.RawXMLINOnlyMessageReceiver
在services.xml文件中:以这种方式配置您的
hello
操作,使其messageReceiver
类的类型为org.apache.axis2.receivers.RawXMLINOnlyMessageReceiver
<operation name="hello">
<messageReceiver class="org.apache.axis2.receivers.RawXMLINOnlyMessageReceiver"/>
</operation>
Then, you can process the incoming XML element inside your hello
method. 然后,您可以在
hello
方法中处理传入的XML元素。
import org.apache.axiom.om.OMElement;
import org.apache.axiom.om.xpath.AXIOMXPath;
import org.jaxen.JaxenException;
public String hello(OMElement xmlElement) {
try {
AXIOMXPath someXPath = new AXIOMXPath("//root/child");
String str = ((OMElement)someXPath.selectSingleNode(node)).getText();
} catch (JaxenException e) {
e.printStackTrace();
}
}
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