[英]How to “return” an array from a function to main in c
I want to pass an arrays index from my function to main. 我想将数组索引从我的函数传递给main。 How can I do that? 我怎样才能做到这一点? For example: 例如:
void randomfunction()
{
int i;
char k[20][10];
for (i=0;i<20;i++)
strcpy(k[i], "BA");
}
int main(int argc, char *argv[])
{
int i; for (i=0;i<20;i++) printf("%s",k[i]);
return 0;
}
I know that for you this is very simple but I've found similar topics and they were too complicated for me. 我知道对您来说这很简单,但是我发现了类似的主题,对我来说它们太复杂了。 I just want to pass the k array to main. 我只想将k数组传递给main。 Of course my purpose is not to fill it with "BA" strings... 当然,我的目的不是用“ BA”字符串填充它。
You want to allocate the memory dynamically. 您要动态分配内存。 Like this: 像这样:
char** randomfunction() {
char **k=malloc(sizeof(char*)*20);
int i;
for (i=0;i<20;i++)
k[i]=malloc(sizeof(char)*10);
//populate the array
return k;
}
int main() {
char** arr;
int i;
arr=randomfunction();
//do you job
//now de-allocate the array
for (i=0;i<20;i++)
free(arr[i]);
free(arr);
return 0;
}
Here is another option. 这是另一种选择。 This works because struct
s can be copied around , unlike arrays. 之所以struct
是因为struct
可以在数组周围复制,这与数组不同。
typedef struct
{
char arr[20][10];
} MyArray;
MyArray random_function(void)
{
MyArray k;
for (i=0;i<sizeof k.arr / sizeof k.arr[0];i++)
strcpy(k.arr[i], "BA");
return k;
}
int main()
{
MyArray k = random_function();
}
Simplest way: 最简单的方法:
void randomfunction(char k[][10])
{
// do stuff
}
int main()
{
char arr[20][10];
randomfunction(arr);
}
If randomfunction
needs to know the dimension 20
, you can pass it as another argument. 如果randomfunction
需要知道20
的维数,则可以将其作为另一个参数传递。 (It doesn't work to put it in the []
, for historial reasons). (出于历史原因,将其放入[]
无效)。
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