在数据库中的IP地址比较

Question

I am trying to solve a problem that could compare 2 columns in a table. the table is as follows

------------------------------------------
|  from    |    to           |  Country  |
------------------------------------------
| 25.0.0.1 | 25.255.255.255  |  denmark  |
------------------------------------------
| 68.0.0.1 | 68.255.255.255  |  USA      |

---

My problem is i have a ip of 25.195.32.0 and i want to compare this to the from and to column and return the country name .

Answer 1

You can use INET_ATON to get a numeric value of the IPs to compare.

SELECT country FROM table
WHERE INET_ATON('25.195.32.0') BETWEEN INET_ATON(from) AND INET_ATON(to)

http://dev.mysql.com/doc/refman/5.7/en/miscellaneous-functions.html#function_inet-aton

Answer 2

根据您使用AND或OR您可以找到使用IN()尝试条件

WHERE from IN('your_ip') OR to IN('your_ip')

Answer 3

Transform IP into integer, then compare integer is simple. MySQL offers the inet_aton function to do so.

select Country from table_name where inet_aton($ip) between inet_aton(`from`) and inet_aton(`ip`);

For performance, you should transform column from , to to integer manully. eg. add to columns from_n , to_n . then your SQL will be like this:

select Country from table_name where inet_aton($ip) between `from_n` and `to_n`

If you are not using MySQL, you should transform $ip into integer $ip_n first (using something like Python's socket.inet_aton ), then replace inet_aton($ip) with $ip_n .

Answer 4

select * from db.table

Then in php (assuming you've run the quest and stored results):

$lookupIP;

for($i=0;$i<$db->getRowCount();$i++) {
    $partsFROM = explode(".", $FROM);
    $partsTO = explode(".", $TO);
    $partsLOOKUP = explode(".",$lookupIP);
    if(
        $partsLOOKUP[0] >= $partsFROM[0] && $partsLOOKUP[0] <= $partsTO[0]  
     && $partsLOOKUP[1] >= $partsFROM[1] && $partsLOOKUP[1] <= $partsTO[1]  
     && etc..
    ) return $Country
}

Not particularly efficient or elegant but you get the idea.

Answer 5

As i interpret from the question, you can use some mask and get the base ip address and then compare it. To use the mask and get base ip, you need to learn something about different classes (A, B, C, D) used from addressing.

Refer this link http://www.subnet-calculator.com/

Answer 6

INET_ATON gives desired solution on IPV4 addresses.

Apart from that, you can also try HEX version of the IP to compare in between.

SELECT  HEX( input_ip_value ) 
BETWEEN HEX( from_ip_column ) 
    AND HEX( to_ip_column )

Example :

mysql> select @i:=hex('25.195.32.0'),
    -> @f:=hex('25.0.0.1'),
    -> @t:=hex('25.255.255.255'),
    -> @i between @f and @t is_between;
+------------------------+---------------------+------------------------------+------------+
| @i:=hex('25.195.32.0') | @f:=hex('25.0.0.1') | @t:=hex('25.255.255.255')    | is_between |
+------------------------+---------------------+------------------------------+------------+
| 32352E3139352E33322E30 | 32352E302E302E31    | 32352E3235352E3235352E323535 |          1 |
+------------------------+---------------------+------------------------------+------------+

Answer 7

Select a range:

SELECT Country FROM table_name WHERE ip_address >= from AND to <= ip_address

If you can use a script (eg php) you could select the entire table and make a mask to the IP. Something like:

We can know what belongs to the network address 192.168.129.3/18 ip as follows:

 ip_en_binario = decbin (ip2long ("192.168.129.3")); mascara_en_binario = decbin (ip2long ("255.255.192.0")); resultado_en_binario $ = $ & $ mascara_en_binario ip_en_binario; miss long2ip (bindec ($ resultado_en_binario)); 

The result returned us this script is 192.168.128.0, which is the network address to which the IP belongs 192.168.129.3/18.

Then, you can do a 'SELECT' of your network with "from" and "to" fields.

Answer 8

使用此查询

select Country from table_name where from=to;