[英]twitterAPI python error : No JSON object could be decoded
I'm using twitterAPI python wrapper https://github.com/geduldig/TwitterAPI 我正在使用twitterAPI python包装器https://github.com/geduldig/TwitterAPI
CONSUMER_KEY = ''
CONSUMER_SECRET = ''
ACCESS_TOKEN_KEY = ''
ACCESS_TOKEN_SECRET = ''
api = TwitterAPI(
CONSUMER_KEY,
CONSUMER_SECRET,
ACCESS_TOKEN_KEY,
ACCESS_TOKEN_SECRET,
# auth_type='oAuth1',
# proxy_url=None
)
r = api.request('account/verify_credentials')
print(r.text)
This is working fine I'm getting proper response so I tried to use filter api of twitter 'statuses/filter' https://dev.twitter.com/docs/api/1.1/post/statuses/filter with 'follow' parameter 这是工作的罚款,我得不到应有的回应,所以我试图用Twitter的状态/过滤器“的过滤器API https://dev.twitter.com/docs/api/1.1/post/statuses/filter与“关注”参数
lst = api.request('statuses/filter', {'follow': 'some_user_id'})
#user_id = 123456789, some 9 digit number lst = api.request('statuses/filter', {'follow': 'some_user_id'})
#user_id = 123456789,约9位数字
I print type of this object print(type(lst))
and I get <class 'TwitterAPI.TwitterAPI.TwitterResponse'>
我打印此对象的print(type(lst))
并得到<class 'TwitterAPI.TwitterAPI.TwitterResponse'>
but when I try to access methods of this class it gives me error No JSON object could be decoded
you can find all the methods of this class here http://twitterapi.readthedocs.org/en/latest/ 但是,当我尝试访问此类的方法时,出现错误消息No JSON object could be decoded
您可以在此处找到此类的所有方法http://twitterapi.readthedocs.org/en/latest/
I have tried all 4 methods print(lst.get_iterator())
,... , print(lst.text)
but same error. 我已经尝试了所有4种方法print(lst.get_iterator())
,..., print(lst.text)
但是有相同的错误。
Any help will be appreciated. 任何帮助将不胜感激。
Once you get a TwitterResponse object with 一旦得到一个TwitterResponse对象,
lst = api.request('statuses/filter', {'follow': 'some_user_id'})
you can iterate the returned stream of statuses using 您可以使用以下方法迭代返回的状态流
for item in lst:
print(item['text'])
You can also get the HTTP status code using 您还可以使用以下命令获取HTTP状态代码
print(lst.status_code)
However, print(lst.text)
will not work because statuses/filter uses a continuous streaming connection. 但是,由于状态/过滤器使用连续的流连接,所以print(lst.text)
将不起作用。
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