[英]mysql multiple join and retrieving only one record from two inner join table
I am in stuck in a query. 我陷入查询中。 Here is my current query.
这是我当前的查询。
SELECT products.product_id, products.product_title,
package_category_products.PCP_id,
product_images.PI_file_name
FROM package_category_products
LEFT JOIN products ON products.product_id = package_category_products.PCP_product_id
-- BEGIN MARKED CODE
LEFT JOIN product_inventories on product_inventories.PI_product_id = products.product_id
INNER JOIN product_images on product_images.PI_product_id = product_inventories.PI_product_id
AND product_images.PI_color = product_inventories.PI_color_id
-- END MARKED CODE
WHERE PCP_package_id = 17
AND PCP_package_category_id = 3
AND product_status ='active'
This query currently return redundant data. 该查询当前返回冗余数据。 I want to use a sub query at the marked code to return only one record from this two table after joining.
我想在标记的代码中使用子查询,以便在加入后仅从这两个表中返回一条记录。 So that I will avoid redundant data and note that I need only one record for each product.
为了避免重复数据,请注意,每个产品只需要一个记录。
Replace "SELECT" by "SELECT DISTINCT": 将“ SELECT”替换为“ SELECT DISTINCT”:
SELECT DISTINCT a.product_id, a.product_title, d.PCP_id, c.PI_file_name
FROM package_category_products as d
LEFT JOIN products as a
ON a.product_id = d.PCP_product_id
LEFT JOIN product_inventories as b on b.PI_product_id = a.product_id
INNER JOIN product_images as c
ON c.PI_product_id = b.PI_product_id AND c.PI_color = b.PI_color_id
WHERE PCP_package_id = 17 AND PCP_package_category_id = 3 AND product_status ='active'
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