如何从 Java 的单行输入中读取多个 Integer 值？

Question

I am working on a program and I want to allow a user to enter multiple integers when prompted. I have tried to use a scanner but I found that it only stores the first integer entered by the user. For example:

Enter multiple integers: 1 3 5

The scanner will only get the first integer 1. Is it possible to get all 3 different integers from one line and be able to use them later? These integers are the positions of data in a linked list I need to manipulate based on the users input. I cannot post my source code, but I wanted to know if this is possible.

Answer 1

I use it all the time on hackerrank/leetcode

    BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
    String  lines = br.readLine();    
        
    String[] strs = lines.trim().split("\\s+");
            
    for (int i = 0; i < strs.length; i++) {
    a[i] = Integer.parseInt(strs[i]);
    }

Answer 2

You want to take the numbers in as a String and then use String.split(" ") to get the 3 numbers.

String input = scanner.nextLine();    // get the entire line after the prompt 
String[] numbers = input.split(" "); // split by spaces

Each index of the array will hold a String representation of the numbers which can be made to be int s by Integer.parseInt()

Answer 3

Try this

public static void main(String[] args) {
    Scanner in = new Scanner(System.in); 
    while (in.hasNext()) {
        if (in.hasNextInt())
            System.out.println(in.nextInt());
        else 
            in.next();
    }
}

By default, Scanner uses the delimiter pattern "\\p{javaWhitespace}+" which matches at least one white space as delimiter. you don't have to do anything special.

If you want to match either whitespace(1 or more) or a comma, replace the Scanner invocation with this

Scanner in = new Scanner(System.in).useDelimiter("[,\\s+]");

Answer 4

Scanner has a method called hasNext():

    Scanner scanner = new Scanner(System.in);

    while(scanner.hasNext())
    {
        System.out.println(scanner.nextInt());
    }

Answer 5

If you know how much integers you will get, then you can use nextInt() method

For example

Scanner sc = new Scanner(System.in);
int[] integers = new int[3];
for(int i = 0; i < 3; i++)
{
    integers[i] = sc.nextInt();
}

Answer 6

Java 8

BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
int arr[] = Arrays.stream(in.readLine().split(" ")).mapToInt(Integer::parseInt).toArray();

Answer 7

Here is how you would use the Scanner to process as many integers as the user would like to input and put all values into an array. However, you should only use this if you do not know how many integers the user will input. If you do know, you should simply use Scanner.nextInt() the number of times you would like to get an integer.

import java.util.Scanner; // imports class so we can use Scanner object

public class Test
{
    public static void main( String[] args )
    {
        Scanner keyboard = new Scanner( System.in );
        System.out.print("Enter numbers: ");

        // This inputs the numbers and stores as one whole string value
        // (e.g. if user entered 1 2 3, input = "1 2 3").
        String input = keyboard.nextLine();

        // This splits up the string every at every space and stores these
        // values in an array called numbersStr. (e.g. if the input variable is 
        // "1 2 3", numbersStr would be {"1", "2", "3"} )
        String[] numbersStr = input.split(" ");

        // This makes an int[] array the same length as our string array
        // called numbers. This is how we will store each number as an integer 
        // instead of a string when we have the values.
        int[] numbers = new int[ numbersStr.length ];

        // Starts a for loop which iterates through the whole array of the
        // numbers as strings.
        for ( int i = 0; i < numbersStr.length; i++ )
        {
            // Turns every value in the numbersStr array into an integer 
            // and puts it into the numbers array.
            numbers[i] = Integer.parseInt( numbersStr[i] );
            // OPTIONAL: Prints out each value in the numbers array.
            System.out.print( numbers[i] + ", " );
        }
        System.out.println();
    }
}

Answer 8

There is more than one way to do that but simple one is using String.split(" ") this is a method of String class that separate words by a spacial character(s) like " " (space)

---

All we need to do is save this word in an Array of Strings.

Warning : you have to use scan.nextLine(); other ways its not going to work(Do not use scan.next();

String user_input = scan.nextLine();
String[] stringsArray = user_input.split(" ");

---

now we need to convert these strings to Integers. create a for loop and convert every single index of stringArray :

for (int i = 0; i < stringsArray.length; i++) {
    int x = Integer.parseInt(stringsArray[i]);
    // Do what you want to do with these int value here
}

Best way is converting the whole stringArray to an intArray :

 int[] intArray = new int[stringsArray.length];
 for (int i = 0; i < stringsArray.length; i++) {
    intArray[i] = Integer.parseInt(stringsArray[i]);
 }

now do any proses you want like print or sum or... on intArray

---

The whole code will be like this :

import java.util.Scanner;
public class Main {
    public static void main(String[] args) {

        Scanner scan = new Scanner(System.in);
        String user_input = scan.nextLine();
        String[] stringsArray = user_input.split(" ");

        int[] intArray = new int[stringsArray.length];
        for (int i = 0; i < stringsArray.length; i++) {
            intArray[i] = Integer.parseInt(stringsArray[i]);
        }
    }
}

Answer 9

This works fine ....

int a = nextInt(); int b = nextInt(); int c = nextInt();

Or you can read them in a loop

Answer 10

Using this on many coding sites:

• CASE 1: WHEN NUMBER OF INTEGERS IN EACH LINE IS GIVEN

Suppose you are given 3 test cases with each line of 4 integer inputs separated by spaces 1 2 3 4 , 5 6 7 8 , 1 1 2 2

        int t=3,i;
        int a[]=new int[4];

        Scanner scanner = new Scanner(System.in);

        while(t>0)  
        {
            for(i=0; i<4; i++){
                a[i]=scanner.nextInt();
                System.out.println(a[i]);
            }   

        //USE THIS ARRAY A[] OF 4 Separated Integers Values for solving your problem
            t--;
        }

• CASE 2: WHEN NUMBER OF INTEGERS in each line is NOT GIVEN

   Scanner scanner = new Scanner(System.in); String lines=scanner.nextLine(); String[] strs = lines.trim().split("\\\\s+");

  Note that you need to trim() first: trim().split("\\\\s+") - otherwise, eg splitting abc will emit two empty strings first

   int n=strs.length; //Calculating length gives number of integers int a[]=new int[n]; for (int i=0; i<n; i++) { a[i] = Integer.parseInt(strs[i]); //Converting String_Integer to Integer System.out.println(a[i]); }

Answer 11

created this code specially for the Hacker earth exam

  Scanner values = new Scanner(System.in);  //initialize scanner
  int[] arr = new int[6]; //initialize array 
  for (int i = 0; i < arr.length; i++) {
      arr[i] = (values.hasNext() == true ? values.nextInt():null);
      // it will read the next input value
  }

 /* user enter =  1 2 3 4 5
    arr[1]= 1
    arr[2]= 2
    and soo on 
 */ 

Answer 12

It's working with this code:

Scanner input = new Scanner(System.in);
System.out.println("Enter Name : ");
String name = input.next().toString();
System.out.println("Enter Phone # : ");
String phone = input.next().toString();

Answer 13

A simple solution can be to consider the input as an array.

Scanner sc = new Scanner(System.in);
int n = sc.nextInt();          //declare number of integers you will take as input
int[] arr = new int[n];     //declare array
for(int i=0; i<arr.length; i++){
    arr[i] = sc.nextInt();   //take values
}

Answer 14

You're probably looking for String.split(String regex). Use " " for your regex. This will give you an array of strings that you can parse individually into ints.

Answer 15

Better get the whole line as a string and then use StringTokenizer to get the numbers (using space as delimiter ) and then parse them as integers . This will work for n number of integers in a line .

    Scanner sc = new Scanner(System.in);
    List<Integer> l = new LinkedList<>(); // use linkedlist to save order of insertion
    StringTokenizer st = new StringTokenizer(sc.nextLine(), " "); // whitespace is the delimiter to create tokens
    while(st.hasMoreTokens())  // iterate until no more tokens
    {
        l.add(Integer.parseInt(st.nextToken()));  // parse each token to integer and add to linkedlist

    }

Answer 16

Using BufferedReader -

StringTokenizer st = new StringTokenizer(buf.readLine());

while(st.hasMoreTokens())
{
  arr[i++] = Integer.parseInt(st.nextToken());
}

Answer 17

When we want to take Integer as inputs
For just 3 inputs as in your case:

import java.util.Scanner;
Scanner scan = new Scanner(System.in);
int a,b,c;
a = scan.nextInt();
b = scan.nextInt();
c = scan.nextInt();

For more number of inputs we can use a loop:

import java.util.Scanner;
Scanner scan = new Scanner(System.in);
int a[] = new int[n]; //where n is the number of inputs
for(int i=0;i<n;i++){
    a[i] = scan.nextInt();    
}

Answer 18

Use Java 8 Streams:

 BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
        try{
          int num_of_arrays=Integer.parseInt(br.readLine());
          while(num_of_arrays>0){

              int[] num = Arrays.stream(br.readLine().split(" ")).mapToInt(Integer::parseInt).toArray();

              num_of_arrays--;
            }

         }

for input:

1

1 2 3

where num_of_arrays = 1 and array elements are in the next line.

Answer 19

This method only requires users to enter the "return" key once after they have finished entering numbers:

It also skips special characters so that the final array will only contains integers

ArrayList<Integer> nums = new ArrayList<>();

    // User input
    Scanner sc = new Scanner(System.in);
    String n = sc.nextLine();

    if (!n.isEmpty()) {
        String[] str = n.split(" ");
        for (String s : str) {
            try {
                nums.add(Integer.valueOf(s));
            } catch (NumberFormatException e) {
                System.out.println(s + " cannot be converted to Integer, skipping...");
            }
        }
    }

Answer 20

//Get user input as a 1 2 3 4 5 6 .... and then some of the even or odd number like as 2+4 = 6 for even number

Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();

        int evenSum = 0;
        int oddSum = 0;

        while (n > 0) {
            int last = n % 10;
            if (last % 2 == 0) {
                evenSum += last;
            } else {
                oddSum += last;
            }

            n = n / 10;
        }

        System.out.println(evenSum + " " + oddSum);

    }
}

Answer 21

if ur getting nzec error, try this:

    try{
        //your code
    }
    catch(Exception e){
        return;
    }

Answer 22

i know it's old discuss :) i tested below code it's worked

`String day = "";
 day = sc.next();
 days[i] = Integer.parseInt(day);`