[英]C++ Multiple Logical Operator
I'm rather new to C/C++. 我是C / C ++的新手。 I have a segment of my application which doesn't seem to work as I'd want but I cannot understand why.
我的应用程序的某个部分似乎无法正常运行,但我不明白为什么。
What I'm looking to do is when the 4 key is in the status of down, I'd like it to carry out the 'idle' function. 我想做的是当4键处于按下状态时,我希望它执行“空闲”功能。 I'd like the idle function to have 2 outcomes.
我希望空闲函数有2个结果。 If the Up OR Down OR Left OR Right OR LMouse AND RButton then carry out the 'movement rotation operation' code else just carry out the standard idle function.
如果向上或向下或向左或向右或LMouse和RButton然后执行“运动旋转操作”代码,否则只需执行标准的空闲功能。 However within my code, it'll loop this while it's down but the moving() will only ever return 0
但是在我的代码中,它会在关闭时循环循环,但是move()只会返回0
I've been messing with it for some time and trying to look on google for answers but I cannot understand why. 我已经弄乱了一段时间,试图在google上寻找答案,但我不明白为什么。
Here's my segment of code: 这是我的代码段:
int moving()
{
int u = GetAsyncKeyState(VK_UP);
int d = GetAsyncKeyState(VK_DOWN);
int l = GetAsyncKeyState(VK_LEFT);
int r = GetAsyncKeyState(VK_RIGHT);
int mr = GetAsyncKeyState(VK_RBUTTON);
int ml = GetAsyncKeyState(VK_LBUTTON);
if(u == 1 || d == 1 || l == 1 || r == 1 || mr == 1 && ml == 1)
{
return 1;
}
}
void idle()
{
cout << "moving = " << moving() << endl;
if(moving() == 1)
{
cout << "Movement rotation operating." << endl;
}
else
{
cout << "This is the idle statement" << endl;
}
}
int main()
{
while(1)
{
if(GetAsyncKeyState('4'))
{
cout << "4 Pressed" << endl;
idle();
}
}
}
Thank you in advance. 先感谢您。
Your logic to determine the button combination needs an extra set of parentheses. 确定按钮组合的逻辑需要额外的括号。
if(u == 1 || d == 1 || l == 1 || r == 1 || (mr == 1 && ml == 1))
Also, 1
will evaluate to true
so you can say 此外,
1
计算结果为true
因此您可以说
if(u || d || l || r || (mr && ml))
You could also make the function return a bool
since that is really what you're after. 您还可以使函数返回
bool
因为这实际上是您要执行的操作。
bool moving()
{
// ...
// code for getting button states
// ...
return (u || d || l || r || (mr && ml))
}
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