如何通过Groovy获取文件build.gradle的完整路径？

Question

I need create file in my java-project near buiid.gradle-file. I must create task (Groovy task) in build.gradle-file, my task must create file near buiid.gradle in my project, but I do not know - how do get path to buiid.gradle-file, that is putting in my project.

How get full path to file buiid.gradle by Groovy? Help me, please.

Answer 1

There are several ways to accomplish this.

1. If you look at the Working With Files page, you can simply use the file() method that is a part of the Project object.
2. If you look at the Project DSL Docs , you should see the projectDir property. Thes properties are available throughout the build.gradle script.

They can be used, respectively, like this:

task myTask << {
    println file('.')
    println projectDir
}

Would output

/full/path/to/your/project/
/full/path/to/your/project/

Where that directory contains the build.gradle file where the task is located.

Answer 2

To get a handle to the java.io.File that represents the currently-executing .gradle file:

def file = buildscript.sourceFile

In my case, I needed the directory of that script so I could apply other configuration from the same directory:

def buildCommonDir = buildscript.sourceFile.getParent()
apply from: "$buildCommonDir/common.gradle"

This approach works with any .gradle file, not just build.gradle.