如何在具有一系列变量的批处理文件中循环执行一组命令？

Question

Here is part of a Windows batch file that I already have:

@echo off
setlocal ENABLEDELAYEDEXPANSION
set files=0
for /F "tokens=*" %%A in (filelist.csv) do (
    SET /A files=!files! + 1
    set var!files!=%%A
)
set var

findstr /i /c:"%var5%" trans.log
if %errorlevel% EQU 0 del %var5%

In this batch file, "filelist.csv" is just a list of files in a particular folder that is automatically generated. The quantity and names of the files in this folder change on a daily basis and when they change the list is updated. There is one file per line in "filelist.csv". The contents of each line in the file are assigned a variable named var1 through varN, and values of these variables correspond to actual file names.

The batch file then searches through another file called "trans.log". In the specific case above it searches for the file that corresponds to "var5". If it finds that file mentioned in "trans.log" then it gets deleted.

What I need to figure out is a way for this last bit of the batch:

findstr /i /c:"%var5%" trans.log
if %errorlevel% EQU 0 del %var5%

to loop for as many times as there are variables "var1" through "varN" and each time it loops, to automatically replace the variable with the next one in the series. So in the case above, if there were 10 files in the list then there would be variables "var1" through "var10". The next time the loop runs from where it is above, it would replace "var5" with "var6" and then "var7", all the way to "var10" and then it would exit the loop and move on to any other commands that come after it in the batch.

Can anyone help me with this, please? TIA

Answer 1

I think this does what you're asking.

@ECHO OFF

@echo off
setlocal ENABLEDELAYEDEXPANSION
set files=0
for /F "tokens=*" %%A in (text.txt) do (
    SET /A files=!files! + 1
    set var!files!=%%A
    for %%i in (!files!) do (CALL :MyFunction !var%%i!)
)
REM
REM Other code can go here...
REM
GOTO END

:MyFunction
ECHO findstr /i /c:"%1" trans.log
ECHO if %errorlevel% EQU 0 del %1

:END

Remove the ECHO statements in MyFunction to actually run findstr and delete the file.

Answer 2

@echo off
setlocal
for /F "skip=4tokens=*" %%A in (filelist.csv) do (
 findstr /i /c:"%%A" trans.log > nul
 if not errorlevel 1 ECHO del %%A
)

This should do what you appear to want to do. Without sample data, testing is impossible.

The skip=4 skips the first 4 lines of filelist.csv and feeds each succeeding line to FINDSTR which sets errorlevel to 0 if the filename is found in trans.log . the if not errorlevel 1 tests for errorlevel being 0 - an the set/test cycle is executed for each line after the first 4 (skipped) lines.

Note that your original scheme would fail (if I understand your purpose correctly) if file5 was not in trans.log . but file6 (or any later) was in trans.log - file5 would be erroneously deleted and the target retained. You'd also get a series of errors for hits after file5 because, having deleted file5 , re-executing the delete on file5 would find it was absent...

Naturally, the del command is simply echo ed - change echo del to del after verification to actually delete the targets.