如何使用SAX Parser解析并获取具有特定类的div元素

Question

This is a snippet of my XML file

<name>Jason</name>
<div class="title">Domain Architect</div>

How do I parse using SAX Parser and obtain the div element with the particular class "title" ?

I am able to parse and obtain all the div elements.
Is there a simple way to obtain the elements that are of a particular class only.

EDIT :

This is how my handler is :

DefaultHandler handler = new DefaultHandler() {

boolean bfname = false;
boolean bdesig = false;

public void startElement(String uri, String localName,String qName, 
            Attributes attributes) throws SAXException {



    if (qName.equalsIgnoreCase("name")) {
        bfname = true;
    }

    if((qName.equalsIgnoreCase("div"))) {
        bdesig = true;
    }


}

public void characters(char ch[], int start, int length) throws SAXException {

    if (bfname) {
        System.out.println("Name : " + new String(ch, start, length));
        bfname = false;
    }

    if(bdesig) {
        System.out.println("Designation : " + new String(ch, start, length));
        bdesig = false;
    }

}

 };

Answer 1

In startElement() the class attribute can be evaluated from the attributes . You then could set a flag if there is an attribute class and you are interested in this particular class (its value). Reset the flag if you are not. Evaluate this flag in characters to retrieve the text contents of the element.

For small documents and non-critical performance you could use XPath to solve this in a more elegant way.