通过表单中的隐藏输入字段传递当前页面的URL
[英]Passing current page URL via hidden input field within form
问题描述
I'm trying to figure out how to pass the URL of a current page via a hidden field so that I can redirect back to that page after the form's input has been handled. 
我试图弄清楚如何通过隐藏字段传递当前页面的URL，以便在处理完表单的输入后可以重定向回该页面。 I've tried using javascript:location.href, however it looks as though it'll pass that as a literal string. 我尝试使用javascript：location.href，但是看起来好像它将作为文字字符串传递。
<input type="url" id="location" name="location" value="javascript:location.href" hidden />
When viewing the page source, I can see that the value of this input box is "javascript:location.href" rather than the page's URL. 查看页面源代码时，我可以看到此输入框的值为“ javascript：location.href”，而不是页面的URL。 Any ideas here? 这里有什么想法吗？ Thanks in advance! 提前致谢！
4 个解决方案
解决方案1
3 2014-05-09 19:59:12
You can access the element in Javascript and change the value there 您可以访问Javascript中的元素并在那里更改值
document.getElementById('location').value = location.href;
Example: http://jsfiddle.net/6zxD5/ 示例： http ： //jsfiddle.net/6zxD5/
解决方案2
0 2014-05-09 19:59:30
I don't think it works that way. 我认为这种方式不起作用。 You could just use the onload callback to insert it when the page is completely loaded: 您可以只在页面完全加载后使用onload回调将其插入：
<body onload="document.getElementById('location').value = document.location.href">
解决方案3
0 2014-05-09 20:04:37
If your document containing the form is already a PHP file , you can do 如果包含表单的文档已经是一个PHP文件，则可以执行
$yourPath = $_SERVER['SERVER_NAME'].$_SERVER['REQUEST_URI'];
And in your html you would do 在你的HTML中，你会做
echo '<input type="url" id="location" name="location" value="'.$yourPath.'" hidden />';
解决方案4
0 2014-05-09 20:05:26
You can use JavaScript to set the value of the hidden field: 您可以使用JavaScript设置隐藏字段的值：
document.getElementById('location').value = window.location.href;
Example: 例：
https://jsfiddle.net/moogs/mhjh0je3/ https://jsfiddle.net/moogs/mhjh0je3/
Since you also tagged PHP, here's the PHP version: 由于您还标记了PHP，因此以下是PHP版本：
<input type="hidden" id="location" name="location" value="<?php echo 'http://'.$_SERVER['HTTP_HOST'].$_SERVER['REQUEST_URI']; ?>" />
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