[英]How to create a “wrapper” in C++?
Update Below 在下面更新
I am trying to create this wrapper to contain pointers to all the other classes. 我正在尝试创建此包装器以包含指向所有其他类的指针。 I've hit this issue (example):
我遇到了这个问题(例子):
main.cpp main.cpp中
struct wrap {
Game* game;
Player* player;
Map* map;
};
game.h game.h
class Game {
private:
wrap* info;
}
Is there a way around this, wrap needs Game, and Game needs wrap. 有没有解决方法,包装需要游戏,游戏需要包装。 (I do know wrapper class [this case struct] is not the best practice, but I am needing that info frequently in other classes.)
(我知道包装类[此案例结构]不是最佳实践,但我在其他类中经常需要该信息。)
Now, I have a new problem. 现在,我有一个新问题。
items.h items.h
// top
struct CoreInfo;
void Items::test() {
struct CoreInfo* b;
//b->testing = 4;
}
(The struct CoreInfo contains a variable "int testing." And I cannot figure out how to access anything within the items class, normal error: 7 request for member 'testing' in 'b', which is of non-class type 'CoreInfo*' (结构CoreInfo包含一个变量“int testing”。我无法弄清楚如何访问items类中的任何内容,正常错误:7请求'b'中的成员'testing',这是非类型的'CoreInfo' *”
just forward declare the wrap struct, as shown below: 只需向前声明wrap结构,如下所示:
main.cpp main.cpp中
#include "game.h"
struct wrap {
Game* game;
Player* player;
Map* map;
};
game.h game.h
struct wrap;
class Game {
private:
struct wrap* info;
}
edit: 编辑:
the problem is that you did not make a separation between declaration and definition by taking advantage of compilation units. 问题是你没有利用编译单元在声明和定义之间进行分离。 If you define your class and its members in a compilation unit (
items.cpp
), while declaring it in the header items.h
, you'll have no trouble. 如果你在编译单元(
items.cpp
)中定义你的类及其成员,在标题items.h
声明它,你就没有问题。
Let's make an example to illustrate this: 让我们举一个例子来说明这一点:
foo.h foo.h中
#include "bar.h"
class A {
B b_instance;
void do_something(int i, int j);
}
foo.cpp Foo.cpp中
#include "foo.h"
int A::do_something(int i, int j) {
return i+j;
}
bar.h bar.h
class B {
A a_instance;
void use_a();
}
bar.cpp bar.cpp
#include "foo.h" // which includes bar.h as well
void B::use_a() {
int k = a_instance.do_something();
}
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