从数据库仅将一个表导入/导出到另一个表（通过PHP）

Question

I want to export only one table from my database and then import it to another database via PHP, i tried do this in phpMyAdmin, i exported from sql-1 in .sql (and gzipped) then imported to sql-2, but when export is complete it's just show me a blank page. so i want to do this via PHP. i have code for export/import for whole database, but i want import/export only one certain table.

here is my code:

Import:

<?php
//ENTER THE RELEVANT INFO BELOW
$mysqlDatabaseName ='db123456789';
$mysqlUserName ='dbo123456789';
$mysqlPassword ='yourPassword';
$mysqlHostName ='db1234.perfora.net';
$mysqlImportFilename ='yourMysqlBackupFile.sql';

//DO NOT EDIT BELOW THIS LINE
//Export the database and output the status to the page
$command='mysql -h' .$mysqlHostName .' -u' .$mysqlUserName .' -p' .$mysqlPassword .' ' .$mysqlDatabaseName .' < ' .$mysqlImportFilename;
exec($command,$output=array(),$worked);
switch($worked){
case 0:
echo 'Import file <b>' .$mysqlImportFilename .'</b> successfully imported to database <b>' .$mysqlDatabaseName .'</b>';
break;
case 1:
echo 'There was an error during import. Please make sure the import file is saved in the same folder as this script and check your values:<br/><br/><table><tr><td>MySQL Database Name:</td><td><b>' .$mysqlDatabaseName .'</b></td></tr><tr><td>MySQL User Name:</td><td><b>' .$mysqlUserName .'</b></td></tr><tr><td>MySQL Password:</td><td><b>NOTSHOWN</b></td></tr><tr><td>MySQL Host Name:</td><td><b>' .$mysqlHostName .'</b></td></tr><tr><td>MySQL Import Filename:</td><td><b>' .$mysqlImportFilename .'</b></td></tr></table>';
break;
}
?>

Export:

<?php
//ENTER THE RELEVANT INFO BELOW
$mysqlDatabaseName ='db123456789';
$mysqlUserName ='dbo123456789';
$mysqlPassword ='myPassword';
$mysqlHostName ='db1234.perfora.net';
$mysqlExportPath ='chooseFilenameForBackup.sql';

//DO NOT EDIT BELOW THIS LINE
//Export the database and output the status to the page
$command='mysqldump --opt -h' .$mysqlHostName .' -u' .$mysqlUserName .' -p' .$mysqlPassword .' ' .$mysqlDatabaseName .' > ~/' .$mysqlExportPath;
exec($command,$output=array(),$worked);
switch($worked){
case 0:
echo 'Database <b>' .$mysqlDatabaseName .'</b> successfully exported to <b>~/' .$mysqlExportPath .'</b>';
break;
case 1:
echo 'There was a warning during the export of <b>' .$mysqlDatabaseName .'</b> to <b>~/' .$mysqlExportPath .'</b>';
break;
case 2:
echo 'There was an error during export. Please check your values:<br/><br/><table><tr><td>MySQL Database Name:</td><td><b>' .$mysqlDatabaseName .'</b></td></tr><tr><td>MySQL User Name:</td><td><b>' .$mysqlUserName .'</b></td></tr><tr><td>MySQL Password:</td><td><b>NOTSHOWN</b></td></tr><tr><td>MySQL Host Name:</td><td><b>' .$mysqlHostName .'</b></td></tr></table>';
break;
}
?>

Answer 1

Why don't you just use MySQL?

CREATE TABLE your_NEW_db_name.your_new_table_name LIKE your_db_name.your_old_table_name;

INSERT your_NEW_db_name.your_new_table_name SELECT * FROM your_db_name.your_old_table_name;