二进制文件的正则表达式

Question

How would you use regular expressions to parse through binary files?

What I have so far

import re

format = re.compile() <--

f.open("input.dat", "rb")

for line in f.readlines():
    data = re.search(format, line)

I'm not sure what to put inside compile as I am only used to writing regex for strings.

specifically I want so break down the format to be:

2 bytes, 2 bytes, 18 bytes

Answer 1

如果您已经知道文件的二进制结构，那么struct unpack是您的朋友。

Answer 2

I'm not sure I understand why you want to parse a binary file with a regex.

Are you saying you want to continually parse the bytes in 2-2-18 byte chunks? In that case, why not just read that many bytes as you go along using standard IO methods?