Django 1.6.4 list_filter

Question

I'm using Django 1.6.4 with Python 3.3. I would like to have, in my admin page, a Search menu to find a name in my table. My project is 'prova' and the model is 'pazienti'. I used this code in models.py:

from django.db import models
from django.contrib import admin
from prova.pazienti.models import *

class Patient(models.Model):
    name = models.CharField(max_length=60)
    surname = models.CharField(max_length=60)
    data_nascita = models.DateField()


class Admin:
    list_display=('name','surname')
    list_filter=('surname',)
    search_fields=('surname',)

But... it doesn't work! I tried also do not insert class Admin in models.py but insert this in admin.py:

from django.contrib import admin
from django.contrib.admin import SimpleListFilter
from django.utils.translation import ugettext_lazy as _
from prova.pazienti.models import *

class PatientAdmin(admin.ModelAdmin):
    list_display=('numero_centro','matricola_pz_centro')
    list_filter=('numero_centro',)
    search_fields=('numero_centro',)

admin.site.register(Patient, PatientAdmin)

admin.site.unregister(Patient)

But the result is the same: no error but I haven't the search bar! Can you help me?

Thank you!

Answer 1

Ok, I find... The code is correct, only in some previous exercise I insert:

admin.site.register(Patient)

in urls.py, so all things wrote in admin.py were ignored! Sorry and thank you