如何计算一个xml文件中相同innerText的数量？

Question

I try to count and then display how many innerText in an xml file are the same. I found this code to count how many equal nodes exists but not how many equal innerText .

var doc = new XmlDocument();
doc.Load(path_to_xml);
var result = from XmlNode n in doc.SelectNodes("//task/*")
             group n by n.InnerText into g
             select new {
                 Text = g.Key,
                 Count = g.Count()
             };

For example, I have an xml like this:

<rootNode>
    <foo>
        <first>stackoverflow</first>
        <second>stackoverflow</second>
        <third>superuser</third>
    </foo>
</rootNode>

Now I should get that result:

stackoverflow: Count 2
superuser: Count 1

Is there a way to do that? I'm parsing the XML using XmlDocument .

Any suggestions? :)

Answer 1

May be this?

Using Linq to Xml:

var result = XDocument.Parse(xml)
    .Descendants("foo")
    .Elements()
    .GroupBy(x => x.Value)
    .ToDictionary(x => x.Key, y => y.Count());

Using XmlDocument:

var doc = new XmlDocument();
doc.LoadXml(xml);

var node = doc.SelectSingleNode("//foo");
var result2 = node.ChildNodes
    .Cast<XmlNode>()
    .GroupBy(x=>x.InnerText)
    .ToDictionary(x => x.Key, y => y.Count());

To show in Messagebox try this:

foreach (var pair in result)
{
    MessageBox.Show(string.Format("{0} found {1} number of times", pair.Key, pair.Value));
}

Answer 2

For the XML that you pasted it would be like this:

var result = from XmlNode n in doc.SelectNodes("/rootNode/foo/*")
             group n by n.InnerText into g
             select new {
                 Text = g.Key,
                 Count = g.Count()
             };

make sure that your XPath is correct...

dumping result to console could be like this:

result.ToList().ForEach(r => Console.WriteLine( r.Text + ": Count " + r.Count));