尝试从PHP中的MySQL数据库显示数据时出现服务器错误

Question

I have a database, db_db which I want to display data from in my browser. 我有一个数据库db_db，它想在浏览器中显示数据。 I have put this php code (display.php) under /var/www/ and trying to access localhost/display.php . 我已将此php代码（display.php）放在/ var / www /下，并尝试访问localhost/display.php 。 Though everytime I come across "Server Error" The website encountered an error while retrieving http://localhost/display.php . 虽然每次遇到“服务器错误”，但网站在检索http://localhost/display.php时都遇到错误。 It may be down for maintenance or configured incorrectly. 可能由于维护原因而停机或配置不正确。

The code is below: 代码如下：

<?php
 //make conn
 $link = mysql_connect('localhost', 'root', '');

 //select db
 mysql_select_db('db_db') or die( "Unable to select db");
 $sql =  "SELECT * FROM results WHERE jobid = 'abc'";
 $records = mysql_query($sql);
?>


<html>
<head>
 <title> Result Info </title>
</head>

<body>
<table width="600" border = "1" cellpadding = "1" cellspacing= "1">
<tr>
 <th>id</th>
 <th>name</th>
<tr>

<?php
 while($result = mysql_fetch_assoc($records)){
   echo "<tr>";
   echo "<td>.$result['id'].</td>";
   echo "<td>.$result['name'].</td>";
   echo "</tr>";
 }//end while
?>

</table>
</body>
</html>

Not sure where am I going wrong. 不知道我要去哪里错了。

Answer 1

There might be the problem with your database select and query syntax. 您的数据库选择和查询语法可能存在问题。 Modify your code 修改你的代码

<?php
 //make conn
 $link = mysql_connect('localhost', 'root', '');

 //select db
 mysql_select_db('db_db', $link) or die( "Unable to select db");
 $sql =  "SELECT * FROM results WHERE jobid = 'abc'";
 records = mysql_query($sql);
?>

Check if it works. 检查它是否有效。 Good luck 祝好运

尝试从PHP中的MySQL数据库显示数据时出现服务器错误

问题描述

1 个解决方案

解决方案1
1 2014-05-14 05:23:31

尝试从PHP中的MySQL数据库显示数据时出现服务器错误

问题描述

1 个解决方案

解决方案1 1 2014-05-14 05:23:31

解决方案1
1 2014-05-14 05:23:31