[英]python one liner code for two nested for loop
How to get the desired result in python one liner ?? 如何在python one liner中获得所需的结果?
object_list=[{'applicationName': "ATM Monitoring",
'roamingDrop': "",
'noOfCustomer': None,
'ipAddress': "192.168.1.1",
'url': "www.google.co.in",},
{'applicationName': None,
'roamingDrop': "",
'noOfCustomer': None,
'ipAddress': "192.168.1.1",
'url': "www.google.co.in",}]
Result required is to replace all None to "" 需要的结果是将所有None替换为“”
object_list=[{'applicationName': "ATM Monitoring",
'roamingDrop': "",
'noOfCustomer': "",
'ipAddress': "192.168.1.1",
'url': "www.google.co.in",},
{'applicationName': "",
'roamingDrop': "",
'noOfCustomer': "",
'ipAddress': "192.168.1.1",
'url': "www.google.co.in",}]
Simple Function to make this happens is : 实现这一目标的简单功能是:
def simple():
for object in object_list:
for key, value in object.iteritems():
if value:
dict( object, **{key: value})
else:
dict(object, **{key: ''})
And Python one unsuccessful one liner: 和Python一个不成功的一个班轮:
[dict(object, **{key: value}) if value else dict(object, **{key: ''})
for object in object_list for key, value in object.iteritems()]
Can the one liner be achieved with list comprehensions? 可以通过列表推导来实现一个班轮吗?
lst=[{'applicationName': "ATM Monitoring",
'roamingDrop': "",
'noOfCustomer': None,
'ipAddress': "192.168.1.1",
'url': "www.google.co.in",},
{'applicationName': None,
'roamingDrop': "",
'noOfCustomer': None,
'ipAddress': "192.168.1.1",
'url': "www.google.co.in",}]
print [{key: val if val else "" for key, val in dct.items()} for dct in lst]
explained: 解释:
dct = lst[0]
{'applicationName': "ATM Monitoring",
'roamingDrop': "",
'noOfCustomer': None,
'ipAddress': "192.168.1.1",
'url': "www.google.co.in",}
Using dictionary comprehension (available since Python 2.7), first just reconstructing the dictionary into the same value: 使用字典理解(从Python 2.7开始提供),首先只需将字典重建为相同的值:
{key: val for dct.items()}
and extending it by assigning "" in case, we have as original value None (or any other value evaluating to False) 并通过分配“”扩展它,以防万一,我们有原始值无(或任何其他值评估为假)
{key: val if val else "" for dct.items()}
Finally (as shown above) it is applied in enveloping list comprehension to all items in the list. 最后(如上所示)它被应用于包含列表理解到列表中的所有项目。
{key: val for dct.items()}
Strictly speaking, this replaces anything, what looks as boolean False by "". 严格地说,这取代了任何东西,看起来像布尔假的“”。
If we want only None
values replaced by ""
, and eg False
and 0
keep as it is, we shall e more strict: 如果我们只想要将None
替换为""
,例如False
和0
保持原样,我们将更加严格:
print [{key: val if val is not None else "" for key, val in dct.items()} for dct in lst]
This seems easy enough: 这似乎很容易:
>>> for d in object_list:
... for k, v in d.items():
... if v is None:
... d[k] = ''
...
and to show what the output looks like: 并显示输出的样子:
>>> import pprint
>>> pprint.pprint(object_list)
[{'applicationName': 'ATM Monitoring',
'ipAddress': '192.168.1.1',
'noOfCustomer': '',
'roamingDrop': '',
'url': 'www.google.co.in'},
{'applicationName': '',
'ipAddress': '192.168.1.1',
'noOfCustomer': '',
'roamingDrop': '',
'url': 'www.google.co.in'}]
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