使用Requests模块Python构建URL
[英]Build a URL using Requests module Python
问题描述
Is it possible to build a URL using the Requests library for Python? 
是否可以使用Python的Requests库构建URL？
Building a query string is supported but what about building the rest of the URL. 支持构建查询字符串但是如何构建URL的其余部分。 Specifically I'd be interested in adding on to the base URL with URL encoded strings: 具体来说，我有兴趣使用URL编码的字符串添加到基本URL：
http :// some address.com/api/[term]/ http：// some address.com/api/[term]/
term = 'This is a test' term ='这是一个测试'
http :// some address.com/api/This+is+a+test/ http：// some address.com/api/This+is+a+test/
This is presumably possible using urllib but it seems like it would be better in Requests. 这可能是使用urllib可能的，但似乎在请求中会更好。 Does this feature exist? 这个功能是否存在？ If not is there a good reason that it shouldn't? 如果没有，是不是有充分的理由不应该？
1 个解决方案
解决方案1
42 已采纳 2014-05-16 02:29:53
requests is basically a convenient wrapper around urllib (and 2,3 and other related libraries). requests基本上是urllib （以及2,3和其他相关库）的方便包装器。
You can import urljoin() , quote() from requests.compat , but this is essentially the same as using them directly from urllib and urlparse modules: 您可以从requests.compat导入urljoin() ， quote() ，但这与直接从urllib和urlparse模块中使用它们基本相同 ：
>>> from requests.compat import urljoin, quote_plus
>>> url = "http://some-address.com/api/"
>>> term = 'This is a test'
>>> urljoin(url, quote_plus(term))
'http://some-address.com/api/This+is+a+test'
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