电子邮件表格无效

Question

I made a website on bootstrap. And by using Ajax and PHP, linked a form to it. The form doesn't send any emails. I have put it on the server to check it as well. Can someone please help me out with the code.

<form name="contactform" method="post" action="" >
                    <div class="form-group">

                        <input type="email" class="form-control" name="email" id="email" placeholder="Enter email" style="width:80%; height: 40px; font-size: 16px; ">
                    </div>
                    <div class="form-group">

                        <input type="password" class="form-control" name="password" id="password" placeholder="Password" style="width:80%; height: 40px; font-size: 16px;">
                    </div>

                    <button type="submit" onclick="myFunction()" class="btn btn-default" style="width: 80%; height: 55px; font-size: 17px; color: white; border-radius: 11px; border: none; background: #F59E3B"><span class="glyphicon glyphicon-play" style="color: white; float: left;"></span>Yes, get me RTD now!</button>
                </form>
                <div id="myDiv"></div>

And this is the AJAX code:

<script type="text/javascript">
function myFunction()
{


    var xmlhttp;
    if (window.XMLHttpRequest)
  {// code for IE7+, Firefox, Chrome, Opera, Safari
    xmlhttp=new XMLHttpRequest();
  }
  else
  {// code for IE6, IE5
    xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
  }
  xmlhttp.onreadystatechange=function()
  {
    if (xmlhttp.readyState==4 && xmlhttp.status==200)
    {
        document.getElementById("myDiv").innerHTML=xmlhttp.responseText;
    }
  }
  var email=document.getElementById("email").value;
  var password=document.getElementById("password").value;
  xmlhttp.open("POST","senderemail.php?email="+email+"&password="+password,true);
  xmlhttp.send();
}
</script>

And here is the PHP code:

    if(isset($_REQUEST["email"]))
{

 $email_to="xxxxx@example.com";
 $email_subject="RTD enquiry ";
 echo $email_from=$_REQUEST["email"];
 $email_message="NEW User:".$email_from;
 echo $password="Password: ". $_REQUEST["password"];

  $email_exp = '/^[A-Za-z0-9._%-]+@[A-Za-z0-9.-]+\.[A-Za-z]{2,4}$/';

  if(!preg_match($email_exp,$email_from)) {

      echo  'OOPS !! It seems you have entered a wrong Email ID.<br />';

  }
  else
  {
   $headers = 'From: '.$email_from."\r\n".'Reply-To: '.$email_from."\r\n" .'X-Mailer: PHP/' . phpversion();
     if(@mail($email_to, $email_subject, $email_message, $headers))
     {
        echo "<div class='thanks'><span id='Nihal'>Many thanks for getting in touch.</span><span class='sub-header'>We'll get back to you as soon as we can.</span></div>";
     }
     else
     { 
       echo "Sorry :( Please try again later";
     }
  }

}

Answer 1

Assuming that there are no other errors than this code should work for you.

If You are sending data with POST then you can't pass query parameters with url. You have to send it separately.

xmlhttp.open("POST","senderemail.php",true);
xmlhttp.setRequestHeader("Content-type","application/x-www-form-urlencoded");
xmlhttp.send("email="+email+"&password="+password);

Answer 2

Do not put the parameters into the URL when using a POST request. Using a post request is fine, though. Add the parameters in the call xmlhttp.send(); ie xmlhttp.send("email="+email+"&password="+password);