[英]Adding links to changing images
So I'm making a page that an image is displayed and every 2 seconds, the image changes using four images within an array. 因此,我正在制作一个页面,其中显示了一个图像,并且每2秒,该图像使用数组中的四个图像进行更改。 I also need to be able to link each image to a different url, however I'm not sure how to do this as everything I've tried hasn't worked, any help is greatly appreciated.
我还需要能够将每个图像链接到不同的url,但是我不确定如何执行此操作,因为我尝试过的所有方法均无效,非常感谢您的帮助。
HTML HTML
<!DOCTYPE html>
<html>
<head>
<script src = "task6.js"></script>
</head>
<body onload="ImageChange()">
<div align="center">
<img src="images/image2.png" id="image" height="200" width="200">
</div>
</body>
</html>
Javascript 使用Javascript
var Cntr = 2;
var images = new Array();
images[0] = "images/image1.png";
images[1] = "images/image2.png";
images[2] = "images/image3.png";
images[3] = "images/image4.png";
function ImageChange()
{
Cntr= Cntr+1;
if (Cntr==4)
{
Cntr=0;
}
document.getElementById("image").src=images[Cntr];
setTimeout("ImageChange()", 2000);
}
JS: JS:
var Cntr = 2;
var images = new Array();
images[0] = "<a href=\"http://google.com/\"><img src=\"images/image1.png\" height=\"200\" width=\"200\"></a>";
images[1] = "<a href=\"http://bing.com/\"><img src=\"images/image2.png\" height=\"200\" width=\"200\"></a>";
images[2] = "<a href=\"http://facebook.com/\"><img src=\"images/image3.png\" height=\"200\" width=\"200\"></a>";
images[3] = "<a href=\"http://stackoverflow.com/\"><img src=\"images/image4.png\" height=\"200\" width=\"200\"></a>";
function ImageChange()
{
Cntr= Cntr+1;
if (Cntr==4)
{
Cntr=0;
}
document.getElementById("container").innerHTML=images[Cntr];
setTimeout("ImageChange()", 2000);
}
HTML: HTML:
<!DOCTYPE html>
<html>
<head>
<script src = "task6.js"></script>
</head>
<body onload="ImageChange()">
<div align="center">
<div id="container"></div>
</div>
</body>
</html>
Wrap your link in A tag 将链接包装在A标签中
Like this 像这样
<a href="" id="mylink"><img src="images/image2.png" id="image" height="200" width="200"></a>
and change your javascript like below. 并按如下所示更改您的JavaScript。
var Cntr = 2;
var images = new Array();
images[0] = "images/image1.png";
images[1] = "images/image2.png";
images[2] = "images/image3.png";
images[3] = "images/image4.png";
var links = new Array();
links[0] = "link1";
links[1] = "link2";
links[2] = "link3";
links[3] = "link4";
function ImageChange()
{
Cntr= Cntr+1;
if (Cntr==4)
{
Cntr=0;
}
document.getElementById("image").src=images[Cntr];
document.getElementById("mylink").href=links[Cntr];
setTimeout("ImageChange()", 2000);
}
You can do simply like that. 您可以简单地那样做。 In html,
在html中,
<body onload="ImageChange()">
<div align="center">
<a href="www.gotoone.com" id="link">
<img src="images/image1.png" id="image" height="200" width="200">
</a>
</div>
In javascript, 在javascript中,
var Cntr = 2;
var images = [
{img : "images/image1.png", link : 'www.gotoone.com'},
{img : "images/image2.png", link : 'www.gotootwo.com'},
{img : "images/image3.png", link : 'www.gotothree.com'},
{img : "images/image4.png", link : 'www.gotofour.com'},
];
function ImageChange()
{
Cntr= Cntr+1;
if (Cntr==4)
{
Cntr=0;
}
document.getElementById("image").src=images[Cntr].img;
document.getElementById("link").href=images[Cntr].link;
setTimeout("ImageChange()", 2000);
}
This should do it. 这应该做。
Markup 标记
<!DOCTYPE html>
<html>
<head>
<script src = "task6.js"></script>
</head>
<body onload="ImageChange(0)">
<div align="center">
<a id="yourLink" href="http::// www.google.com">
<img src="img/google.png" />
</a>
</div>
</body>
</html>
JavaScript JavaScript的
var link = document.getElementById("yourLink"),
image = link.getElementsByTagName("img")[0],
images = [{
image: 'url1.png', href: 'url1.com'
}, {
image: 'url2.png', href: 'url2.com'
}, {
image: 'url3.png', href: 'url3.com'
}, {
image: 'url4.png', href: 'url4.com'
}];
function ImageChange(target) {
link.href = images[target].href;
image.src = images[target].image;
window.setTimeout(function() {
ImageChange(++target%image.length);
}, 2000);
}
Is this what you are looking for ? 这是你想要的 ?
<body onload="ImageChange()">
<div>
<a id="link" target="_blank" href="http://www.google.com">
<img src="http://www.picturesnew.com/media/images/Austin-Healey-Photo.jpg" id="image" height="200" width="200"/>
</a>
</div>
</body>
var i = 0;
var img = [
{
src:"http://blog.gettyimages.com/wp-content/uploads/2013/01/Siberian-Tiger-Running-Through-Snow-Tom-Brakefield-Getty-Images-200353826-001.jpg",
href:"http://www.google.com"
},
{
src:"http://www.picturesnew.com/media/images/cool-images.jpg",
href:"http://www.google.com"
},
{
src:"http://blog.gettyimages.com/wp-content/uploads/2013/01/Siberian-Tiger-Running-Through-Snow-Tom-Brakefield-Getty-Images-200353826-001.jpg",
href:"http://www.google.com"
},
{
src:"http://www.picturesnew.com/media/images/images-background.jpg",
href:"http://www.google.com"
},
{
src:"http://blog.gettyimages.com/wp-content/uploads/2013/01/Simple-Living-Rhiannon-Llewelyn-Taxi-Getty-Images-81938225.jpg",
href:"http://www.google.com"
}
]
function ImageChange(){
console.log("Source " + i + " : " +document.getElementById("image").src)
if (i==4){
i=0;
}
i++;
document.getElementById("image").src=img[i].src;
document.getElementById("link").href=img[i].href;
setTimeout("ImageChange()", 2000);
}
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