如何通过AngularJS中的templateUrl传递URL参数？

Question

Trying to learn AngulareJS got stuck with this.

This is the code :

app.config(function ($routeProvider){
$routeProvider
.when('/',
{       
    templateUrl: '/sort',
    controller : 'tasksController'      
})  
.when('/expression/:expressionId/type/:typeId',
{   
    templateUrl: '/sort/'+:expressionId +'/'+ :typeId,
    controller : 'tasksController'  
})});

This is obviously wrong.

Can any one please tell me what is the correct way to do this? Thanks.

Answer 1

Thanks guys,this is what I wanted

.when('/expression/:expressionId/type/:typeId', {

templateUrl: function(params) {
    return '/sort/' + params.expressionId +'/'+ params.typeId ;
},
controller: 'tasksController'
});

Answer 2

Probably you are looking for $routeparams https://docs.angularjs.org/api/ngRoute/service/ $routeParams.

you can do something like below:

app.config(function ($routeProvider){
  $routeProvider
    .when('/',{
        templateUrl: '/sort',
        controller : 'tasksController'
    })
    .when('/expression/:expressionId/type/:typeId', {
        templateUrl: '/sort',
        controller : 'tasksController'
    })
});

app.controller('tasksController', ['$scope', '$routeparams', function($scope, $routeparams) {
    var expressionId = $routeparams.expressionId
        , typeId = $routeparams.typeId;
}]);