无法从UITableViewCell调用performSegueWithIdentifier

Question

I am having trouble resolving this issue. I have declared a segue via the storyboard and I'm trying to call it from a custom TableViewCell I wrote to handle the dynamic prototype.

- (IBAction)clickedPhoto:(id)sender {
[self performSegueWithIdentifier:@"PhotoDetail" sender:self];
}

I'm getting a No visible @interface for 'PhotoChoiceTableViewCell' declares the selector 'performSegueWithIdentifier:sender:' error.

I think I've figured out that I need to call the segue from a UIView but I can't figure out how to implement the proper delegate or protocol to do this.

My UITableViewController is called InboxViewController and my UITableViewCell is called PhotoChoiceTableViewCell.

Thank you!

Answer 1

Call the performSegueWithIdentifier on your view controller. The cell does not implement this method.

Step 1. Implement a protocol.

@class MyCell;
@protocol MyDelegate <NSObject>

- (void)photoTappedInCell:(MyCell *)cell;

@end


@interface MyCell : UITableViewCell

@property (nonatomic, weak) id<TRUProductImageGalleryCellDelegate> delegate;

@end

Step 2.

Call a delegate in your cell:

- (IBAction)deleteButtonTapped:(id)sender
{
    if ([_delegate respondsToSelector:@selector(photoTappedInCell:)])
    {
        [_delegate performSelector:@selector(photoTappedInCell:) withObject:self];
    }
}

And remenber to set your view controller as a delegate when you're configuring the cell.