如何在JavaScript或jQuery中过滤JSON数据？

Question

How to filter JSON data using Javascript or jQuery?

This my JSON data:

[{"name":"Lenovo Thinkpad 41A4298","website":"google"},
{"name":"Lenovo Thinkpad 41A2222","website":"google"},
{"name":"Lenovo Thinkpad 41Awww33","website":"yahoo"},
{"name":"Lenovo Thinkpad 41A424448","website":"google"},
{"name":"Lenovo Thinkpad 41A429rr8","website":"ebay"},
{"name":"Lenovo Thinkpad 41A429ff8","website":"ebay"},
{"name":"Lenovo Thinkpad 41A429ss8","website":"rediff"},
{"name":"Lenovo Thinkpad 41A429sg8","website":"yahoo"}]

JavaScript:

obj1 = JSON.parse(jsondata);

now I only want name and website data which is contain website is equal to "yahoo"

Answer 1

This is how you should do it : ( for google find)

$([
  {"name":"Lenovo Thinkpad 41A4298","website":"google222"},
  {"name":"Lenovo Thinkpad 41A2222","website":"google"}
  ])
    .filter(function (i,n){
        return n.website==='google';
    });

Better solution : ( Salman's)

$.grep( [{"name":"Lenovo Thinkpad 41A4298","website":"google"},{"name":"Lenovo Thinkpad 41A2222","website":"google"}], function( n, i ) {
  return n.website==='google';
});

http://jsbin.com/yakubixi/4/edit

Answer 2

No need for jQuery unless you target old browsers and don't want to use shims.

var yahooOnly = JSON.parse(jsondata).filter(function (entry) {
    return entry.website === 'yahoo';
});

In ES2015:

const yahooOnly = JSON.parse(jsondata).filter(({website}) => website === 'yahoo');

Answer 3

Try this way, allow you even filter by other key

data:

var my_data = [{"name":"Lenovo Thinkpad 41A4298","website":"google"},
{"name":"Lenovo Thinkpad 41A2222","website":"google"},
{"name":"Lenovo Thinkpad 41Awww33","website":"yahoo"},
{"name":"Lenovo Thinkpad 41A424448","website":"google"},
{"name":"Lenovo Thinkpad 41A429rr8","website":"ebay"},
{"name":"Lenovo Thinkpad 41A429ff8","website":"ebay"},
{"name":"Lenovo Thinkpad 41A429ss8","website":"rediff"},
{"name":"Lenovo Thinkpad 41A429sg8","website":"yahoo"}];

usage:

//We do that to ensure to get a correct JSON
var my_json = JSON.stringify(my_data)
//We can use {'name': 'Lenovo Thinkpad 41A429ff8'} as criteria too
var filtered_json = find_in_object(JSON.parse(my_json), {website: 'yahoo'});

filter function

function find_in_object(my_object, my_criteria){

  return my_object.filter(function(obj) {
    return Object.keys(my_criteria).every(function(c) {
      return obj[c] == my_criteria[c];
    });
  });

}

Answer 4

The following code works for me:

 var data = [{"name":"Lenovo Thinkpad 41A4298","website":"google"}, {"name":"Lenovo Thinkpad 41A2222","website":"google"}, {"name":"Lenovo Thinkpad 41Awww33","website":"yahoo"}, {"name":"Lenovo Thinkpad 41A424448","website":"google"}, {"name":"Lenovo Thinkpad 41A429rr8","website":"ebay"}, {"name":"Lenovo Thinkpad 41A429ff8","website":"ebay"}, {"name":"Lenovo Thinkpad 41A429ss8","website":"rediff"}, {"name":"Lenovo Thinkpad 41A429sg8","website":"yahoo"}] var data_filter = data.filter( element => element.website =="yahoo") console.log(data_filter) 

Answer 5

You can use jQuery each function as it is explained below:

Define your data:

var jsonStr = '[{"name":"Lenovo Thinkpad 41A4298,"website":"google"},{"name":"Lenovo Thinkpad 41A2222,"website":"google"},{"name":"Lenovo Thinkpad 41Awww33,"website":"yahoo"},{"name":"Lenovo Thinkpad 41A424448,"website":"google"},{"name":"Lenovo Thinkpad 41A429rr8,"website":"ebay"},{"name":"Lenovo Thinkpad 41A429ff8,"website":"ebay"},{"name":"Lenovo Thinkpad 41A429ss8,"website":"rediff"},{"name":"Lenovo Thinkpad 41A429sg8,"website":"yahoo"}]';

Parse JSON string to JSON object:

var json = JSON.parse(jsonStr);

Iterate and filter:

$.each(JSON.parse(json), function (idx, obj) {
    if (obj.website == 'yahoo') {
        // do whatever you want
    }
});

Answer 6

The values can be retrieved during the parsing:

 var yahoo = [], j = `[{"name":"Lenovo Thinkpad 41A4298","website":"google"}, {"name":"Lenovo Thinkpad 41A2222","website":"google"}, {"name":"Lenovo Thinkpad 41Awww33","website":"yahoo"}, {"name":"Lenovo Thinkpad 41A424448","website":"google"}, {"name":"Lenovo Thinkpad 41A429rr8","website":"ebay"}, {"name":"Lenovo Thinkpad 41A429ff8","website":"ebay"}, {"name":"Lenovo Thinkpad 41A429ss8","website":"rediff"}, {"name":"Lenovo Thinkpad 41A429sg8","website":"yahoo"}]` var data = JSON.parse(j, function(key, value) { if ( value.website === "yahoo" ) yahoo.push(value); return value; }) console.log( yahoo ) 

Answer 7

I know the question explicitly says JS or jQuery, but anyway using lodash is always on the table for other searchers I suppose.

From the source docs :

var users = [
  { 'user': 'barney', 'age': 36, 'active': true },
  { 'user': 'fred',   'age': 40, 'active': false }
];

_.filter(users, function(o) { return !o.active; });
// => objects for ['fred']

// The `_.matches` iteratee shorthand.
_.filter(users, { 'age': 36, 'active': true });
// => objects for ['barney']

// The `_.matchesProperty` iteratee shorthand.
_.filter(users, ['active', false]);
// => objects for ['fred']

// The `_.property` iteratee shorthand.
_.filter(users, 'active');
// => objects for ['barney']

So the solution for the original question would be just one liner:

var result = _.filter(data, ['website', 'yahoo']);

Answer 8

It iterates through the json objects, and searches each value you are concerned about, 'website', and if it equals "yahoo" you can then return that value or do whatever you like there. Right now it just logs that element to the console.

jsonObj.forEach(function (element, index) {
    if(element['website'] === 'yahoo'){
        console.log('found', element)   
    }
})