[英]C++ inherit template class
I've got a peculiar request, hopefully it's not too far fetched and can be done. 我有一个奇怪的要求,希望它不是太遥远,可以做到。
I've got a template class 我有一个模板类
template<class T> class Packable
{
public:
// Packs a <class T> into a Packet (Packet << T)
virtual sf::Packet& operator <<(sf::Packet& p) const = 0;
friend sf::Packet& operator <<(sf::Packet& p, const T &t);
friend sf::Packet& operator <<(sf::Packet& p, const T *t);
// Packs a Packet into a <class T> (T << Packet)
virtual T operator <<(sf::Packet& p) const = 0;
friend T& operator <<(T &t, sf::Packet& p);
friend T* operator <<(T *t, sf::Packet& p);
// Unpacks a Packet into a <class T> (Packet >> T)
virtual sf::Packet& operator >>(sf::Packet& p) const = 0;
friend sf::Packet& operator >>(sf::Packet& p, T &);
friend sf::Packet& operator >>(sf::Packet& p, T* t);
};
and I want to be able to use it something like 我希望能够像它一样使用它
class Player : public Packable
{
//...
}
Such that Player now has all of those operators overloaded for it. 这样玩家现在已经为它重载了所有这些运算符。
As of now, I get Expected class name
as a compile error. 截至目前,我将
Expected class name
作为编译错误。 Is there a way to accomplish this without needing to specify the class? 有没有办法在不需要指定类的情况下完成此操作? That is to say;
也就是说; how can
Packable
pick up Player
as <class T>
when I inherit it? 当我继承它时,
Packable
怎么能把Player
当作<class T>
?
I guess you want something like the following: 我想你想要的东西如下:
class Player: public Packable<Player>
//...
Yes, you need to do 是的,你需要这样做
template <typename T>
class Player: public Packable<T>
{
...
}
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