如何从字符串中间获取2个字符？

Question

import time

date = time.strftime("%d:%m:%y")


print date #returns '18:05:14'

print date[-2:] #returns '14'

print date[:2] #returns '18'

#print ??? <-returns '05'

How can I (preferably) use the [: number :] thing to look for the 4th and 5th character ONLY of "18:05:14" (05)? if i can't use [:#], that's fine. I can't find any possible way, but any help is appreciated.

Answer 1

Specify a start and stop position:

>>> date = '18:05:14'
>>> date[3:5]
'05'
>>>

[3:5] will get every character from index 3 inclusive to index 5 exclusive.

Answer 2

You have many ways to get value.

print(date[3:5])           # 05 (start the 4th to 5th char)
print(date.split(":")[1])  # 05 (split string and get 2nd string)