PHP，如何检查查询是否成功运行，否则重定向到其他页面而没有显示错误

Question

this is the create function as i have added the database class.

id------int 
name----var
fname---var       
phone---number 

i will run here the query which is not valid the (phone) value should be number so i will insert text to have wrong query.

public function create(){
$sql = "Insert into tbl_one (name,fname,phone) values('nameN','nameF',error)";
if($database->query($sql)){
 $this->id = $database->insert_id();
} else {
redirect_to('index.php');
}

now here how i can make if the query is false it should redirect me to one page, currently it will show the mysql_error and will give detail why it's wrong but i dont want it i want it just check the query if false redirect me to other page. do i need another function or that where i should get the hint to move on

Answer 1

you have to replace error with 0

public function create(){
$sql = "Insert into tbl_one (name,fname,phone) values('nameN','nameF',0)";
if($database->query($sql)){
 $this->id = $database->insert_id();
} else {
redirect_to('index.php');
}

Answer 2

use exception handling

try {

    $sql = "Insert into tbl_one (name,fname,phone) values('nameN','nameF',error)";
    $database->query($sql);
    $this->id = $database->insert_id();

}catch(Exception $e){
    //log exception...$e

    redirect_to('index.php');
}