新窗口中的弹出窗口将在新选项卡中打开

Question

I have a calendar created with php. In this calendar I have load_id's listed by date. I made a popup to show more data for each load. I want it to show as a popup not in a new tab. I have tried doing it as a function but as I don't know javascript I could not figure out how to pass the load_id to the url. If I replace "this.href" with the url in a function it works like a charm. But again I don't know how to pass the load id as a variable so that won't work for me. If someone could point out where I made my mistake passing the variable I would be much obliged!

This is what I have now:

echo "<span class='load_shipped'>
<a href='cal_popup.php?load_id=".$load_id."'
onclick='window.open(this.href, '_blank','left=100,top=100,width=500,height=500,toolbar=1,resizable=0');'>
".$load_id."
</a>
<br>
</span>\n";

I tried this as well to no avail:

echo "<span class='load_shipped'>
<a onclick='popup(".$load_id.");'>".$load_id."</a><br>
</span>\n";

Javascript:

<script>
    function popup(id){
        window.open('cal_popup.php?load_id=id', '_blank','left=100, top=100,width=500,height=500,toolbar=1,resizable=0');
    }
</script>

All this did though was pass 'id' instead of the real load_id.

Answer 1

Seems like you're having trouble because you're using the same quotes to wrap the attribute onclick and to define the parameters of the window.open call. Try using double quotes on the attribute. You'll also need to return false; at the end of the onclick to prevent the link working as normal.

echo "<span class='load_shipped'>
    <a href='cal_popup.php?load_id=".$load_id."'
    onclick=\"window.open(this.href, '_blank','left=100,top=100,width=500,height=500,toolbar=1,resizable=0');return false;\">
    ".$load_id."
    </a>
    <br>
</span>\n";

In your last example where you have the function popup - please note that you need to concatenate the id variable into the string like 'cal_popup.php?load_id=' + id .