将表行复制到另一个表HTML

Question

Fiddle

I have two tables. When I click on one table row it will copy to another table, and I will change the button as my requirement. Please help me.

$(window).load(function() {
                var items = [];

                $(".addBtn").on("click", function() {
                    var newTr = $(this).closest("tr").clone();

                    var newButtonHTML = "<input type = 'button' value='Edit' onclick='Edit()' /><input type='button' value='Delete' onclick='deleteRow(this.parentNode.parentNode.rowIndex)'/>";
                    $(newButtonHTML).children("button").click(function(e) {
                    });

                    $(newTr).children("td:last").html("").html(newButtonHTML);
                    items.push(newTr);
                    newTr.appendTo($("#stopsTable"));

                });

Answer 1

At your example it was a wrong selector

$('#myTable.tr') 

instead of

$('#myTable tr')

Check fixed version: http://jsfiddle.net/V7wXD/7/

Best regards!

Answer 2

Js:

$(function() {
    $('#myTable tbody tr').each(function(){
        $(this).append('<td><button class="copy">Copy</button></td>');
    });

    $(document).on('click', 'button.copy', function(){
        var $tr = $(this).parents('tr:first').clone();

        $tr.appendTo($('#stopsTable > tbody'));
    });
});

Test here:

http://jsfiddle.net/V7wXD/8/