如何在Android中读取JSON数组
[英]How to read json array in Android
问题描述
I am facing here problem in reading a json array which is got from server : http://XXX.XXX.XXX.XXX:9090/appsapi/rest/services/getStudentPersonalDetails/123789 , this json array doesn't have json object in it. 
我在读取从服务器获取的json数组时遇到问题： http : //XXX.XXX.XXX.XXX : 9090/appsapi/rest/services/getStudentPersonalDetails/123789 ，此json数组中没有json对象它。 It is like below.: 如下所示：
{"password":"raj","address":"dfsaf","state":"tamilnadu","image":"Bindu Appalam.jpg",
"dept":"BE(Mech)","fname":"fasdf","mname":"saffd","dob":"14/12/1951","sex":"Male",
"email":"fdasd@gmail.com","contact":"212121212545855555545","city":"dsfadf",
"pin":"600106","sname":"fdjsf","studid":"123789"}
I want to parse it.. 我想解析它。
I have tried to get the json array like below from httpclient request : 我试图从httpclient请求中获取如下所示的json数组：
try {
System.out.println("url tt : "+url);
// http client
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpEntity httpEntity = null;
HttpResponse httpResponse = null;
System.out.println(" Urls Input to "+url);
// Checking http request method type
if (method == POST) {
HttpPost httpPost = new HttpPost(url);
// adding post params
if (params != null) {
httpPost.setEntity(new UrlEncodedFormEntity(params));
}
httpResponse = httpClient.execute(httpPost);
} else if (method == GET) {
// appending params to url
System.out.println(" Params Valyes "+params);
if (params != null) {
String paramString = URLEncodedUtils.format(params, "utf-8");
url += "?" + paramString;
System.out.println(" Params String "+paramString);
}
HttpGet httpGet = new HttpGet(url);
httpResponse = httpClient.execute(httpGet);
}
httpEntity = httpResponse.getEntity();
response = EntityUtils.toString(httpEntity);
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
but got below error in response : 但响应以下错误：
05-20 16:38:25.420: I/System.out(29983):
Output <!DOCTYPE html><html><head><title>Apache Tomcat/8.0.5 - Error report
</title><style type="text/css">H1 {font-family:Tahoma,Arial,sans-serif;color:white;background-color:#525D76;font-size:22px;}
H2 {font-family:Tahoma,Arial,sans-serif;color:white;background-color:#525D76;font-size:16px;}
H3 {font-family:Tahoma,Arial,sans-serif;color:white;background-color:#525D76;font-size:14px;}
BODY {font-family:Tahoma,Arial,sans-serif;color:black;background-color:white;}
B {font-family:Tahoma,Arial,sans-serif;color:white;background-color:#525D76;}
P {font-family:Tahoma,Arial,sans-serif;background:white;color:black;font-size:12px;}A {color : black;}A.name
{color : black;}.line {height: 1px; background-color: #525D76; border: none;}</style> </head><body><h1>HTTP Status 404 - Not Found
</h1><div class="line"></div><p><b>type</b> Status report</p><p><b>message</b> <u>Not Found</u></p><p><b>description</b>
<u>The requested resource is not available.</u></p><hr class="line"><h3>Apache Tomcat/8.0.5</h3></body></html>
any body , pls help here... 任何人，请在这里帮助...
3 个解决方案
解决方案1
3 2014-05-20 12:15:30
In your code, there is no json array present, it is json object with name value pair data. 在您的代码中，不存在json数组，它是具有名称值对数据的json对象。 So you have to parse JSONObject not JSONArray . 因此，您必须解析JSONObject而不是JSONArray 。
Like: 喜欢：
JSONObject json = new JSONObject(jsonString);
String password = json.getString("password");
Similarly you can get all the values of the object. 同样，您可以获取对象的所有值。
解决方案2
1 2014-05-20 11:50:27
A JSON Object starts with a { and ends with a } while a JSON Array starts with a [ and ends with a ]. JSON对象以{开头，以}结尾，而JSON数组以[开头，以]结尾。
In your case, change your code to have a JSONObject instead. 根据您的情况，将代码更改为具有JSONObject。
JSONObject json = new JSONObject(jsonString);
JSONArray jArray = json.getJSONArray("list");
System.out.println("*****JARRAY*****"+jArray.length());
for(int i=0;i<jArray.length();i++){
JSONObject json_data = jArray.getJSONObject(i);
Log.i("log_tag","_id"+json_data.getInt("account")+
", mall_name"+json_data.getString("name")+
", location"+json_data.getString("number")+
", telephone"+json_data.getString("url")+
",----"+json_data.getString("balance")+
",----"+json_data.getString("credit")+
",----"+json_data.getString("displayName")
);
}
refer to: https://stackoverflow.com/a/4244963/2771869 请参阅： https : //stackoverflow.com/a/4244963/2771869
解决方案3
1 2014-05-20 11:57:11
Kindly refer online for how to get JSON Response. 请在线参考如何获取JSON响应。
http://mrbool.com/how-to-use-json-to-parse-data-into-android-application/28944 http://mrbool.com/how-to-use-json-to-parse-data-into-android-application/28944
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