[英]Do mailto links in Android need to be URL encoded for mail Intents to work?
Environment: 环境:
Windows Server 2012 Standard Windows Server 2012标准版
Android Studio 0.5.8 - android-19 Android Studio 0.5.8-android-19
JRE 1.7.0_51 JRE 1.7.0_51
Description of problem: 问题描述:
Overriding URL loading in an Android web view to start an email intent fails to identify mailto properties. 在Android Web视图中覆盖URL加载以启动电子邮件意图无法识别mailto属性。
MailTo.parse("mailto:?subject=Something%20interesting%20from%20Google&body=GooglePlus%20(%20https://google.com/plus%20)")
returns: 返回:
key: "to" value: "/plus)"
when email intent is prepared by: 通过以下方式准备电子邮件意图时:
Intent intent = new Intent(Intent.ACTION_SENDTO); intent.putExtra(Intent.EXTRA_EMAIL, new String[] { address }); intent.putExtra(Intent.EXTRA_TEXT, body); intent.putExtra(Intent.EXTRA_SUBJECT, subject); intent.putExtra(Intent.EXTRA_CC, cc); intent.addFlags(Intent.FLAG_ACTIVITY_MULTIPLE_TASK); intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK); intent.setType("message/rfc822"); intent.setData(Uri.parse("mailto:")); // only email apps should handle this return intent;
then: 然后:
if (url.startsWith("mailto:")) { MailTo mailTo = MailTo.parse(url); Intent intent = newEmailIntent(mailTo.getTo(), mailTo.getSubject(), mailTo.getBody(), mailTo.getCc()); _mainActivity.startActivity(Intent.createChooser(intent, "Send Email...")); return true; }
If I remove the colon in the transfer protocol or replace it with %3a then the subject and body are parsed as expected. 如果我在传输协议中删除了冒号或将其替换为%3a,则将按预期解析主题和正文。
Question : in the title ^. 问题 :标题中的^。
Thanks in advance. 提前致谢。
It appears that MailTo has a problem parsing a mailto: URL which contains within the subject or body fields characters that appear in a URL (eg : and /). 似乎MailTo在解析mailto:URL时遇到问题,该URL在主题或正文字段中包含出现在URL中的字符(例如:和/)。 I encountered this when trying to parse a mailto URL which contained a web URL in the body field (ie I wanted the email body to contain a link that the recipient could click). 在尝试解析在主体字段中包含Web URL的mailto URL时,我遇到了此问题(即,我希望电子邮件主体包含收件人可以单击的链接)。
What I did to overcome this is to make a modified copy of the MailTo class (called MailTo2), and modified the parse method to be as follows: 我要克服的问题是制作MailTo类的修改副本(称为MailTo2),并将parse方法修改如下:
/**
* Parse and decode a mailto scheme string. This parser implements
* RFC 2368. The returned object can be queried for the parsed
* parameters.
* @param theUrl String containing a mailto URL
* @return MailTo2 object
* @exception IllegalArgumentException if the URL scheme is not mailto.
*/
public static MailTo2 parse(String theUrl)
throws IllegalArgumentException
{
MailTo2 theMailTo2 = null;
String theNoSchemeUrl = null;
String theQuery = null;
Uri theEmailUri = null;
int thePos = 0;
// Validate the given URL.
if (theUrl == null)
{
throw new NullPointerException();
}
if (!isMailTo(theUrl))
{
throw new IllegalArgumentException("Not a mailto scheme: " + theUrl);
}
// Strip the scheme as the URI parser can't cope with it.
theNoSchemeUrl = theUrl.substring(MAILTO_SCHEME.length());
// Get the query part of the URL.
thePos = theNoSchemeUrl.indexOf('?');
if (thePos >= 0)
{
theQuery = theNoSchemeUrl.substring(thePos+1);
theNoSchemeUrl = theNoSchemeUrl.substring(0, thePos);
}
// Create a URL from the URL string (without scheme and query).
theEmailUri = Uri.parse(theNoSchemeUrl);
// Construct the MailTo2 instance which will be returned.
theMailTo2 = new MailTo2();
// Parse out the query parameters
if (theQuery != null)
{
String[] theQueryParts = theQuery.split("&");
String theName = null;
String theValue = null;
for (String theQueryPart : theQueryParts)
{
thePos = theQueryPart.indexOf('=');
if (thePos <= 0) continue;
theName = theQueryPart.substring(0, thePos);
theValue = theQueryPart.substring(thePos+1).trim();
// insert the headers with the name in lower-case so that
// we can easily find common headers
theMailTo2.HEADERS.put(Uri.decode(theName).toLowerCase(Locale.ROOT),
Uri.decode(theValue));
}
}
// Address can be specified in both the headers and just after the
// mailto line. Join the two together.
String address = theEmailUri.getPath();
if (address != null)
{
String addr = theMailTo2.getTo();
if (addr != null)
{
address += ", " + addr;
}
theMailTo2.HEADERS.put(TO, address);
}
return theMailTo2;
}
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