如何在100个字符后的第一个空格后拆分长字符串

Question

I have a long string and want to split it into segments of +/- 100 characters if it has more than 100 otherwise not. That means I have for example this string:

string input

"asld asö öasdn askdn asklcanscklans cakslcna acsklcnasclk ncaslkcnas casld asö öasdn askdn asklcanscklans cakslcna acsklcnasclk ncaslkcnas c"

and need these 2 strings out of it

1: "asld asö öasdn askdn asklcanscklans cakslcna acsklcnasclk ncaslkcnas casld asö öasdn askdn asklcanscklans"
2: "cakslcna acsklcnasclk ncaslkcnas c"

As you can see, I need to split them after the first space, after the 100th character.

I'm clueless how to do that with .split()

Answer 1

You can use indexOf to search your string for a specified character, indexOf also provides an optional argument for a starting index in your string, giving you the position from which you can substring or do whatever you need to do:

string.indexOf(' ',100);

If you want to perform further splits you can use a loop to run back over the results and perform the same action.

There are some suggestions of using regex here which may be fine, all I would say is if you want to use Regex then go away and get an understanding of what the pattern does. Using code you don't understand makes your life difficult later on.

Answer 2

怎么样string.split(/(.{100}\\S*)\\s/).filter(function(e){return e;});

Answer 3

You can find the first space after position 100 as:

var index = string.indexOf(' ', 100);

You want to split after this space, so your second part starts at:

var splitPoint = string.indexOf(' ', 100) + 1;

If the string is not 100 characters long, or there is no space after position 100, then splitPoint is zero (because indexOf returns -1), and you don't want to split.

So you can split the string as:

if (splitPoint > 0) {
  var part1 = string.substring(0, splitPoint);
  var part2 = string.substring(splitPoint);
  // Do something with the parts.
}

Answer 4

As explained in the documentation , you can use a RegExp with split, and capture a part of it using capture groups.

var s = "asld asö öasdn askdn asklcanscklans cakslcna acsklcnasclk ncaslkcnas casld asö öasdn askdn asklcanscklans cakslcna acsklcnasclk ncaslkcnas c";
s.split(/(.{100}[^\s]*)\s/);

// 1 : "asld asö öasdn askdn asklcanscklans cakslcna acsklcnasclk ncaslkcnas casld asö öasdn askdn asklcanscklans"
// 2 : "cakslcna acsklcnasclk ncaslkcnas c"

And to remove the empty element(s), you can use the filter method :

s.split(/(.{100}[^\s]*)\s/).filter(function(s) {
    return s.length > 0;
});

Answer 5

You can easily do that using substr

var your_string = "asld asö öasdn askdn asklcanscklans cakslcna acsklcnasclk ncaslkcnas casld asö öasdn askdn asklcanscklans cakslcna acsklcnasclk ncaslkcnas c"

var string1 = your_string.substr(0,105);
var string2 = your_string.substr(106,your_string.length)