[英]How can I overload the assignment operator in c++
Ive been reading this article: https://www.thc.org/root/phun/unmaintain.html , and Ive been trying to implements steps Misleading names
(search for isValid(x)
) and How To Fix Unused Variable Errors
(#29 under Miscellaneous Techniques). 我一直在阅读这篇文章: https : //www.thc.org/root/phun/unmaintain.html ,我一直在尝试实现
Misleading names
(搜索isValid(x)
)以及How To Fix Unused Variable Errors
(#杂项技术下的29)。
I wish to do something more useful, (also according to the article) as doing more stuff on less lines is better. 我希望做一些更有用的东西(也是根据文章),因为在更少的线上做更多的东西会更好。
Unfortunately, I have no idea on how to overload the assignment operator for a basic type. 不幸的是,我不知道如何为基本类型重载赋值运算符。 I know I could do something like
operator=(&Other o)
if I was using a class, but alas, C/C++ doesn't take after Java by having classes for some basic types... 我知道如果我使用的是类,我可以做类似
operator=(&Other o)
,但是,唉,C / C ++不会因为某些基本类型的类而需要Java之后...
Unfortunately, I have no idea on how to overload the assignment operator for a basic type.
不幸的是,我不知道如何为基本类型重载赋值运算符。 I know I could do something like
operator=(&Other o)
if I was using a class我知道如果我使用的是类,我可以做类似
operator=(&Other o)
You cannot overload operators for built-in types in C++. 您不能在C ++中为内置类型重载运算符。 And that's the end of the story.
这就是故事的结局。
but alas, C/C++ doesn't take after Java by having classes for some basic types...
但是,C / C ++并没有采用Java来为一些基本类型提供类...
...You make it sound like Java's distinction between int
and Integer
is somehow a good thing :) ...你听起来像Java在
int
和Integer
之间的区别在某种程度上是一件好事:)
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