[英]sql - insert a new row for every customer id that is in the table
I am using SQL server 2008. The following is my table: 我正在使用SQL Server2008。下表是我的表:
Cust_id Date rate type
3579 12/05/2014 0.01256 f
5200 13/05/2014 0.02365 f
1234 18/05/2014 0.05623 m
3456 23/05/2014 0.01254 m
7896 23/05/2014 0.01254 f
2589 21/05/2014 0.01254 m
3698 23/05/2014 0.01254 f
I would like to select all the customers that are type 'm' (that is easy enough) and I would like to insert a new row of Date,rate and type for each customer that is found. 我想选择所有类型为'm'的客户(这很容易),我想为找到的每个客户插入新的Date,rate和type行。 so the result would look something like this:
所以结果看起来像这样:
Cust_id Date rate type
1234 18/05/2014 0.05623 m
1234 16/05/2014 0.02222 f
3456 23/05/2014 0.01254 m
3456 27/05/2014 0.03333 f
2589 21/05/2014 0.01254 m
2589 20/05/2014 0.01111 f
I will not be able to insert rows individually because I have over 5000 customers :-(. Could some experts assist me. 我将无法单独插入行,因为我有5000多个客户:-(。有些专家可以协助我。
Thanks a ton in advance. 在此先感谢一吨。
If you can compute required Date
, Rate
and Type
from selected Date
, Rate
and Type
you can use insert..select construction: 如果可以从选定的
Date
, Rate
和Type
计算所需的 Date
, Rate
和Type
,则可以使用insert..select构造:
insert into Customers(
Cust_id,
Date,
Rate,
Type)
select Cust_id,
Date, -- TODO:Generate required Date from given one
Rate, -- TODO:Generate required Rate from given one
Type -- TODO:Generate required Type from given one
from Customers
where Type = 'm'
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