获取PHP数组中的MySQL列名称

Question

Can someone please help me how to get my MySQL column names out in my while loop? My code goes like this:

if (mysqli_connect_errno()) {
    echo "MySQL failed: " . mysqli_connect_errno();
}

if (isset($_GET['date'])) {
    $get_date = $_GET['date'];
    $result = mysqli_query($conn, "SELECT * FROM stats WHERE form_date = '$get_date'");
    $col = array();
    while ($row = mysqli_fetch_array($result)) {
        $col[] = $row['year'];
        $col[] = $row['month'];
        $col[] = $row['day'];
        $col[] = $row['weekday'];
        $col[] = $row['form_date'];
        $col[] = $row['name'];
        $col[] = $row['count'];
        $col[] = $row['lang'];
    }
    echo "<pre>";
    print_r($col);
    echo "</pre>";
    mysqli_close($conn);
} else {
    echo "Please set a date value in URL parameter ?date=[YYYY-MM-DD]";
}

My returned array then looks like this:

Array
(
    [0] => 2014
    [1] => 01
    [2] => 01
    [3] => Wednesday
    [4] => 2014-01-01
    [5] => Michael K
    [6] => 41
    [7] => SE
    [8] => 2014
    [9] => 01
    [10] => 01
    [11] => Wednesday
    [12] => 2014-01-01
    [13] => Nicklas S
    [14] => 40
    [15] => DK
    [16] => 2014
    [17] => 01
    [18] => 01
    [19] => Wednesday
    [20] => 2014-01-01
    [21] => Jesper S
    [22] => 5
    [23] => SE
)

However I would like my array to get returned like this:

Array
(
    [year] => 2014
    [day] => 01
    [month] => 01
    [weekday] => Wednesday
    [form_date] => 2014-01-01
    [name] => Michael K
    [count] => 41
    [lang] => SE
    [year] => 2014
    [month] => 01
    [day] => 01
    [weekday] => Wednesday
    [form_date] => 2014-01-01
    [name] => Nicklas S
    [count] => 40
    [lang] => DK
    [year] => 2014
    [month] => 01
    [day] => 01
    [weekday] => Wednesday
    [form_date] => 2014-01-01
    [name] => Jesper S
    [count] => 5
    [lang] => SE
)

So the keys in my array matches the column names I have in my database. I just can't seem to wrap my head around how I do this. Can someone help? :-)

Answer 1

Change

$col = array();
while ($row = mysqli_fetch_array($result)) {
    $col[] = $row['year'];
    $col[] = $row['month'];
    $col[] = $row['day'];
    $col[] = $row['weekday'];
    $col[] = $row['form_date'];
    $col[] = $row['name'];
    $col[] = $row['count'];
    $col[] = $row['lang'];
}

to

$col = array();
while ($row = mysqli_fetch_array($result, MYSQLI_ASSOC)) {
    $col[] = $row;
}

print_r($col);

mysql_fetch_array() has second argument. This optional parameter is a constant indicating what type of array should be produced from the current row data. The possible values for this parameter are the constants MYSQLI_ASSOC, MYSQLI_NUM, or MYSQLI_BOTH.

Answer 2

You are looking for mysqli_fetch_assoc() which fetches results as an associative array (column => value).

Then try this:

while ($row = mysqli_fetch_assoc($result)) {
    echo "<pre>";
    print_r($row);
    echo "</pre>";
}

Answer 3

You can not use an associative array like this because it will have duplicate key indices, which is not allowed. I suggest you work with a restructured array to have each "group" of keys as a nested array.

Answer 4

使用mysql_assoc_array()代替mysq_fetch_array()