从数据库和数组加载选择框值

Question

I have a code that will first load all the values into an array. The values will be then given to select box. There will be totally 5 select boxes and it will load the same data. I have tried my level best. And here is the code

    <?php
    $resultSet = array();
    while($result = mysql_fetch_array($result_book_query))
    {
    $resultSet['Book_Code'][] = $result['Book_Code'];
    $resultSet['Book_Name'][] = $result['Book_Name'];
    }
    ?>

    <?php for($i=1; $i<=5; $i++) { ?>
    <select name="book_code_<?php echo $i; ?>" id="book_code">
    <option value=""></option>
    <option value="<?php  echo $resultSet['Book_Code'];?>"><?php  echo $resultSet['Book_Name'] ;?></option>
    </select>
    <?php } ?>

What I'm trying to do is.

Show 5 select box with the same values (ie the values wil be first loaded from DB and stored in array) and then load it inside the select box.

Thanks, Kimz

Answer 1

This is not very handy way to operate with database results, seems as copy-pasted from an example with little understanding. Try it this way:

<?php
$resultSet = array();
while($result = mysql_fetch_array($result_book_query))
{
    $resultSet[] = $result; //the code you had here is maybe working, but very unhandy
}
?>

<?php for($i=1; $i<=5; $i++) { ?>
  <select name="book_code_<?php echo $i; ?>" id="book_code">
  <option value=""></option>
  <?php foreach ($resultSet as $result) { //THIS is the important thing you missed
?>
    <option value="<?php  echo htmlspecialchars($result['Book_Code']);?>"><?php  echo htmlspecialchars($result['Book_Name']) ;?></option>
  <? } ?>
</select>
<?php } ?>

Also, ALWAYS escape variables written to HTML using htmlspecialchars.

Answer 2

Alright, so as per the comment below, you can do:

<?php for($i=1; $i<=5; $i++) { ?>
<select name="book_code_<?php echo $i; ?>" id="book_code">
<option value=""></option>
<?php foreach($resultSet['Book_Code'] as $k=>$v){
   echo "<option value=".$v.">".$resultSet['Book_Name'][$k]."</option>";
}
?>
</select>
<?php } ?>

Answer 3

<?php
$resultSet = array();
while($result = mysql_fetch_array($result_book_query))
{
$resultSet[] = array(
                    'Book_Code' => $result['Book_Code'],
                    'Book_Name' => $result['Book_Name']
                    );
}
?>

<?php for($i=1; $i<=5; $i++): ?>
<select name="book_code_<?php echo $i; ?>" id="book_code">
<option value=""></option>
<?php foreach($resultSet as res):?>
    <option value="<?php  echo $res['Book_Code'];?>"><?php  echo $res['Book_Name'] ;?></option>
<?php endforeach;?>

</select>
<?php endfor;} ?>