鼠标悬停时的下拉菜单应保持可见

Question

The button with dropdown menu should be visible when the mouse is moved inside the div which works fine but the problem is that when I move the mouse out of that div, I want the button and dropdown menu to remain visible if menu is dropped down but the button should get hidden if menu is not dropped down.How can I achieve this?(in the given code, button and dropdown menu get hidden on mouseout no matter what)

<div id="img_container" name="img_container" onmouseover="f()" onmouseout ="g()">
            <img src="image/images.jpg"  alt="Cover" >
            <div class="btn-group" id="cov" name="cov" >
               <button  class="btn dropdown-toggle" data-toggle="dropdown">Action
               </button>
               <ul class="dropdown-menu">
    <!-- dropdown menu links -->
                <li><a href="#">Secondary link</a></li>
            <li><a href="#">Something else here</a></li>
            <li class="divider"></li>
            <li><a href="#">Another link</a></li>
               </ul>
            </div>
        </div>


function f(){
      document.getElementById("cov").style.display="inline-block";
  }

  function g(){
      document.getElementById("cov").style.display="none";
  }

Fiddle

Answer 1

Instead of set the style to display none , use the .show() and .hide() in jquery to show and hide the specific div

$('#cov').hide();

function f() {
    //document.getElementById("cov").style.display = "inline-block";
    $('#cov').show();
}

function g() {
    // $('#cov').hide();
   //document.getElementById("cov").style.display = "none";
}

JSFiddle to show div when mouse over

Answer 2

If I am understanding you correctly you want something like this:

var list = document.getElementById("dropdown-menu");
var menu = document.getElementById("cov");

function dropdown() {
    if (list.style.display == "none") {
        list.style.display = "block";
    } else {
        list.style.display = "none";
    }
}

function f() {
    menu.style.display = "block";
}

function g() {
    if (list.style.display == "none") {
        menu.style.display = "none";
    } else if (list.style.display == "block"){
        menu.style.display = "block";
    } else {menu.style.display = "block"}
}

Here is a DEMO

Answer 3

Try this fiddle , hope this is what you are looking for.

You don't need onmouseout ="g()"

Update

try this updated fiddle