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Python装饰器在Django上检查POST参数

[英]Python decorator to check for POST parameters on Django

I have code that read like this to check if POST parameters are included on the request: 我有这样读取的代码,以检查请求中是否包含POST参数:

def login(request):
    required_params = frozenset(('email', 'password'))
    if required_params <= frozenset(request.POST):
        # 'email' and 'password' are included in the POST request
        # continue as normal
        pass
    else:
        return HttpResponseBadRequest()

When the list of required POST parameters is big, this code gets messy. 当所需的POST参数列表很大时,此代码将变得混乱。 What I would like to do is something like: 我想做的是这样的:

@required_POST_params('email', 'password')
def login(request):
    # 'email' and 'password' are here always!
    pass

Then I'm confident that both 'email' and 'password' POST parameters are included in the request, because if not, the request would automatically return HttpResponseBadRequest() . 然后,我有信心在请求中同时包含“ email”和“ password” POST参数,因为如果没有,则请求将自动返回HttpResponseBadRequest()

Is there a way that Django allows me to do this, and if it doesn't, how can I do it by myself with a decorator? Django是否有办法允许我执行此操作,如果不允许,我如何可以自己使用装饰程序来执行此操作?

You would need a custom decorator, but you can take require_http_methods as a base example: 您将需要一个自定义装饰器,但是您可以将require_http_methods作为一个基本示例:

def require_post_params(params):
    def decorator(func):
        @wraps(func, assigned=available_attrs(func))
        def inner(request, *args, **kwargs):
            if not all(param in request.POST for param in params):
                return HttpResponseBadRequest()
            return func(request, *args, **kwargs)
        return inner
    return decorator

Example usage: 用法示例:

@require_post_params(params=['email', 'password'])
def login(request):
    # 'email' and 'password' are here always!
    pass

FYI, require_http_methods source code . 仅供参考, require_http_methods源代码

Try with this . 试试这个

Instead of require.POST() , try with require.POST('email', 'password') . 代替require.POST() ,请尝试require.POST('email', 'password')

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