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如何使用jQuery删除与父级相似的类似HTML标签?

[英]How to remove similar HTML tag close to parent using jquery?

Here is my HTML code: 这是我的HTML代码:

<div class="img-area text-center frustrated">
<img class="delete" style="height: 12px; float:right; padding-right:5px; cursor: pointer;" src="/linkmo/images/closeicon.png" offset="2">
<a class="loc" href="#">
<img id="imagelocation2" class="imagelocation" style="height:110px; width:105px;" alt="" src="/linkmo/upload/224927120.jpg" offset="2">
</a>
</div>

When the user clicks on image having class delete then I change the src attribute in img tag with the ID imagelocation2 using ajax. 当用户单击具有类delete图像时,我将使用ajax更改ID为imagelocation2 img标签中的src属性。

What I want is that when image src is changed the img tag having the class delete should be removed. 我想要的是,当更改图像src时,应delete具有delete类的img标签。

What I have tried in my ajax success function: 我在ajax成功功能中尝试过的工作:

 $('#imagelocation' + id).attr('src', '/linkmo/images/placeholder.png');//Changes the src of img tag, works fine
 $('.delete img[offest='+id+'').remove();//Does not work
 $('#imagelocation' + id).parent().closest(".delete").remove();//Does not work

What I am doing wrong here? 我在这里做错了什么?

USe like this find instead of closest 喜欢这样find而不是closest

$('#imagelocation' + id).parent().find(".delete").remove();

Because closest search for the parent elements. 因为closest搜索父元素。 While find search for child elements. find搜索子元素。

您可以使用.siblings()的目标与一流的图像.delete

$('#imagelocation' + id).siblings('.delete').remove();

You have a type in your javascript. 您的JavaScript类型。

$('.delete img[offest='+id+'').remove();

should be 应该

$('.delete img[offset='+id+']').remove();

offest -> offset 最差->偏移

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