AngularJS：如何过滤对象阵列除了一个属性

Question

Angular $filter can do string fuzzy search for Object Array,

But every of My Objects have one property of base64 pic.

var MyObjects = [{
    property1: 'ab',
    property2: 'cd',
    pic: '4AAQSkZJRgABAQEASABIAAD/2wBDAAMCAgMCAgMDAwMEAwMEBQgFBQQEBQoHBw.....' 
}, {
    property1: 'ef',
    property2: 'gh',
    pic: '4AAQSkZJRgABAQEASABIAAD/2wBDAAMCAgMCAgMDAwMEAwMEBQgFBQQEBQoHBw.....' 
}, {
    ....


}],

result = $filter('filter')(MyObjects, $scope.searchText);

How can I except pic property in fuzzy search?

Answer 1

Angular's filter can take a function as an argument to filter your array. The filter will select items that the function returns true for.

You can use this feature to achieve what you want.

Here is the official documentation

So, you could do something like this to compare the search text only with the two properties you want to:

var filterFunction = function(item) {
    var val = $scope.searchText
    return item.property1.indexOf(val || '') !== -1 || item.property2.indexOf(val || '') !== -1;
}

result = $filter('filter')(MyObjects, filterFunction, $scope.searchText);

Here's a fiddle demonstrating this effect.

Answer 2

This is the way I ended up implementing it. Angular custom filters seem to be the way to go for this sort of problem. You can find more about them from Angular , but in this implementation you can add any other fields you'd like to leave off by adding another && key != "unwantedKey" . The value of the key must be a string for the indexOf to work so the typeof portion makes sure we don't get any ids that are numbers, etc.

$scope.search = function(item){ 
    for (var key in item){
        if (typeof key === "string" && key != "pic"){ 

            if(item[key].indexOf($scope.query) > -1){
                return true;
            }
        }
    }
    return false;
};