如何从我的python脚本执行fabfile？

Question

I have a fabfile and here are the contents:

[root@ip-10-10-20-82 bakery]# cat fabfile.py
from fabric.api import run
def deploy():
        run('wget -P /tmp https://s3.amazonaws.com/LinuxBakery/httpd-2.2.26-1.1.amzn1.x86_64.rpm')
        run('sudo yum localinstall /tmp/httpd-2.2.26-1.1.amzn1.x86_64.rpm')

I can execute the fabfile successfully when it is run from the command line like so:

fab -f fabfile.py -u ec2-user -i id_rsa -H 10.10.15.242 deploy

The problem is that it it does not work when I run it from within my Python script. This is how it is run within my script:

import subprocess
subprocess.call(['fab', '-f', '/home/myhome/scripts/bakery/fabfile.py', '-u ec2-user', '-i', 'id_rsa', '-H', bakery_internalip, 'deploy'])

This is the error which I am getting:

Fatal error: Fabfile didn't contain any commands!
Aborting.

I don't understand why I am getting this error.

Answer 1

Change fabfile.py and add these few changes.

@task
def deploy(): 
    ... rest of the code

if __name__ == "__main__":
    local('fab -f /path/fabfile.py deploy')

Then run it in python