Python-如果没有日期模式，则跳过

Question

I have a csv where I have for example this:

Date,Comment

2014-05-29,Last time we will see

What about next time?"

2014-05-29,"""still want to be seen as the good guys..."""

This is my world. 

2014-05-29,And so the game begins... ;)

2014-05-29,"Btw, this is... 

And I would like to skip those rows which have not a date format in first column. I have this:

a = []
csvReader = csv.reader(open(csv_file_to_open, 'rb'), delimiter=',')
for row in csvReader:
    a.append(row)

for row in a:
    if row[0] == "date format then": <= here I need some pattern filter but I don't know how to do it
        print 'yes'

Date is always in format %Y-%m-%d .

Answer 1

You can use the datetime module to check this:

import datetime
a = []
csvReader = csv.reader(open(csv_file_to_open, 'rb'), delimiter=',')
for row in csvReader:
    a.append(row)

for row in a:
    try:
        datetime.datetime.strptime(row[0],'%Y-%m-%d')
        print 'yes'
    except ValueError:
        continue

This should do it!