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laravel 4-将多个控制器中的相似数据拉入许多视图

[英]laravel 4 - pull similar data in multiple controllers into many views

I have users routes like that: 我有这样的用户路线:

user/13/posts/10 用户/ 13 /文章/ 10
user/13/videos/443 用户/ 13 /视频/ 443
user/13/items/4002 用户/ 13 /项目/ 4002

And i want to pull all the data related to 'user/13' every time posts/videos/items views are loaded. 我想每次加载帖子/视频/项目视图时提取与“ user / 13”相关的所有数据。 i am also loading the sidebar @include('inc/blog-sidebar') and this file contain data that is the same in all the views and related to 'user/13'. 我还加载了侧边栏@include('inc / blog-sidebar'),此文件包含的数据在所有视图中都相同,并且与'user / 13'有关。

what is the best way to pull all this information without doing it per function within every controller? 提取所有这些信息而不在每个控制器中按功能执行的最佳方法是什么?

I have tried view:composer within the routes.php (which is bad) and i could not get the user id and get the relevant information. 我已经尝试了route.php中的view:composer(这很糟糕),但我无法获取用户ID并获取相关信息。

View::composer('posts.show', function($view)
{
    $author = User::find(1);
    $view->with('author',$author);
});

also, if this is the best solution then where should i store my view composer? 另外,如果这是最好的解决方案,那么我应该在哪里存储View Composer?

Thanks! 谢谢!

To automatically populate views with data using view composers: 要使用视图编辑器自动向视图填充数据,请执行以下操作:

At first create a route pattern for any URI like user/13 or user/15 like this (In routes.php file): 首先,为这样的任何URI例如user/13user/15创建一个路由模式(在routes.php文件中):

// Composers will be used only for this url pattern, i.e. "user/13" or "user/15"
Route::when('user/*', 'prepareView');

Then create the prepareView filter like this: 然后创建如下的prepareView过滤器:

Route::filter('prepareView', function($route, $request) {

    // Register your three view composers
    View::composers(array(
        // Call the "postsViewComposer" method from
        // ViewComposers for "posts.show" view
        'ViewComposers@postsViewComposer' => 'posts.show',

        // Call the "videsViewComposer" method from
        // ViewComposers for "videos.show" view
        'ViewComposers@videsViewComposer' => 'videos.show',

        // Call the "itemsViewComposer" method from
        // ViewComposers for "items.show" view
        'ViewComposers@itemsViewComposer' => 'items.show',
    ));

});

Then create the ViewComposers class in app/viewcomposers folder: 然后在app/viewcomposers文件夹中创建ViewComposers类:

class ViewComposers {

    public function postsViewComposer($view)
    {
         // Get user id, for example, 15
        $id = Route::current()->parameter('id');

        // Then use it to retrieve the model   
        $author = User::find($id);
        return $view->with('author', $author);
    }

    public function videsViewComposer($view)
    {
        // Logic for this view composer
    }

    public function itemsViewComposer($view)
    {
        // Logic for this view composer
    }
}

Finally, you need to add your new class in your composer.json file in autoload->classmap like: 最后,您需要在autoload->classmap中的composer.json文件中添加新class ,如下所示:

"autoload": {
    "classmap": [
        "app/commands",
        "app/controllers",
        // ...
        "app/viewcomposers"
]

At last, just run the composer dump-autoload from your command prompt/terminal from within your project's root directory. 最后,只需从项目的根目录中的command prompt/terminal运行composer dump-autoload That's it. 而已。 Now whenever a URI for any user with any id will be requested, those view composers will run to prepare the views. 现在,每当请求具有任何id任何用户的URI时,这些view composers就会运行以准备视图。

I think you are talking about eager loading. 我认为您是在谈论急切的加载。 You can approach this way, 你可以这样

User::with('posts','videos')->get();

See, Eager Loading 请参阅急切加载

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