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合并Arduino草图(MIDI)

[英]Merge Arduino Sketches (MIDI)

This is a very beginner level question. 这是一个非常初学者的问题。 I need some guidance on how to merge these two sketches into one. 我需要一些有关如何将这两个草图合并为一个的指导。 I have only some very beginner level knowledge of Arduino language. 我对Arduino语言只有一些非常初级的知识。

I have successfully tested both sketches independently, I just need to compile them together in some way now. 我已经成功地独立测试了两个草图,现在只需要以某种方式将它们编译在一起即可。

Any help or guidance would be appreciated! 任何帮助或指导将不胜感激! Thank you advance! 谢谢你提前!

Sketch 1: 草图1:

// stomp using usb midi

#include <Bounce.h>

// midi channel
int channel = 1;

Bounce button1 = Bounce(2, 5);
Bounce button2 = Bounce(4, 5);
Bounce button3 = Bounce(6, 5);
Bounce button4 = Bounce(8, 5);

void setup()
{
  pinMode(2, INPUT_PULLUP);
  pinMode(4, INPUT_PULLUP);
  pinMode(6, INPUT_PULLUP);
  pinMode(8, INPUT_PULLUP);

}

void loop()
{
  button1.update();
  button2.update();
  button3.update();
  button4.update();

  if (button1.fallingEdge())
  {
    usbMIDI.sendNoteOn(60, 99, channel); // 60 = C4
  }
  if (button2.fallingEdge())
  {
    usbMIDI.sendNoteOn(62, 99, channel); // 62 = D4
  }
  if (button3.fallingEdge())
  {
    usbMIDI.sendNoteOn(64, 99, channel); // 64 = E4
  }
  if (button4.fallingEdge())
  {
    usbMIDI.sendNoteOn(68, 99, channel); // 68 = F4
  }


//Note On message when button is released

if (button1.risingEdge()) {
    usbMIDI.sendNoteOff(60, 0, channel); 
  }
  if (button2.risingEdge()) {
    usbMIDI.sendNoteOff(62, 0, channel); 
  }
  if (button3.risingEdge()) {
    usbMIDI.sendNoteOff(64, 0, channel); 
  }
  if (button4.risingEdge()) {
    usbMIDI.sendNoteOff(68, 0, channel); 

}
}

Sketch 2: 草图2:

int previous;
int current; 

void setup() {
}

void loop () {
  current = map(analogRead(11), 136, 1023, 0 , 127);
  usbMIDI.sendControlChange(7, current, 1);
  delay(5); 
}

Ok, at first glance your variables should be fine (although you don't seem to be using 'int previous' in sketch 2?): 好的,乍一看,您的变量应该没问题(尽管您似乎未在草图2中使用'int previous'?):

#include <Bounce.h>

int channel = 1; 
Bounce button1 = Bounce(2, 5); 
Bounce button2 = Bounce(4, 5); 
Bounce button3 = Bounce(6, 5); 
Bounce button4 = Bounce(8, 5); 
int previous; 
int current;

Setup also looks straightforward, as you don't set anything up in the 2nd sketch: 安装程序看起来也很简单,因为您没有在第二个草图中进行任何设置:

void setup()
{
  pinMode(2, INPUT_PULLUP);
  pinMode(4, INPUT_PULLUP);
  pinMode(6, INPUT_PULLUP);
  pinMode(8, INPUT_PULLUP);

}

The final bit is stitching together the two loops. 最后一位将两个循环缝合在一起。 From what I can tell, the 'channel' variable is what links them, ie when you say 据我所知,“ channel”变量是链接它们的内容,即当您说

usbMIDI.sendControlChange(7, current, 1);

the last '1' is the channel number, selectable from 1 to 16. So does this mean you could do the following: 最后一个“ 1”是通道号,可以在1到16之间选择。这是否意味着您可以执行以下操作:

usbMIDI.sendControlChange(7, current, channel);

and if so, do you want to change/control channels before or after your sendNoteOn/Off stuff? 如果是这样,您是否要在sendNoteOn / Off之前或之后更改/控制频道? eg if before, would the following work: 例如,如果以前可以进行以下工作:

// stomp using usb midi

#include <Bounce.h>

// midi channel
int channel = 1;
Bounce button1 = Bounce(2, 5);
Bounce button2 = Bounce(4, 5);
Bounce button3 = Bounce(6, 5);
Bounce button4 = Bounce(8, 5);
int previous;
int current;

void setup()
{
  pinMode(2, INPUT_PULLUP);
  pinMode(4, INPUT_PULLUP);
  pinMode(6, INPUT_PULLUP);
  pinMode(8, INPUT_PULLUP);    
}

void loop()
{
  current = map(analogRead(11), 136, 1023, 0 , 127);
  usbMIDI.sendControlChange(7, current, channel);
  delay(5); 

  button1.update();
  button2.update();
  button3.update();
  button4.update();

  if (button1.fallingEdge())
  {
    usbMIDI.sendNoteOn(60, 99, channel); // 60 = C4
  }
  if (button2.fallingEdge())
  {
    usbMIDI.sendNoteOn(62, 99, channel); // 62 = D4
  }
  if (button3.fallingEdge())
  {
    usbMIDI.sendNoteOn(64, 99, channel); // 64 = E4
  }
  if (button4.fallingEdge())
  {
    usbMIDI.sendNoteOn(68, 99, channel); // 68 = F4
  }


//Note On message when button is released

if (button1.risingEdge()) {
    usbMIDI.sendNoteOff(60, 0, channel); 
  }
  if (button2.risingEdge()) {
    usbMIDI.sendNoteOff(62, 0, channel); 
  }
  if (button3.risingEdge()) {
    usbMIDI.sendNoteOff(64, 0, channel); 
  }
  if (button4.risingEdge()) {
    usbMIDI.sendNoteOff(68, 0, channel); 

}
}

I don't have a midi device so I can't test this... 我没有Midi设备,所以无法测试...

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