基于新行的java字符串拆分

Question

I have following string

String str="aaaaaaaaa\n\n\nbbbbbbbbbbb\n   \n";

I want to break it on \\n so at the end i should two string aaaaaaaa and bbbbbbbb . I dont want last one as it only contain white space. so if i split it based on new line character using str.split() final array should have two entry only.

I tried below:

String str="aaaaaaaaa\n\n\nbbbbbbbbbbb\n   \n".replaceAll("\\s+", " ");
String[] split = str.split("\n+");

it ignore all \\n and give single string aaaaaaaaaa bbbbbbbb .

Answer 1

Delete the call to replaceAll() , which is removing the newlines too. Just this will do:

String[] split = str.split("\n\\s*");

This will not split on just spaces - the split must start at a newline (followed by optional further whitespace).

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Here's some test code using your sample input with edge case enhancement:

String str = "aaaaaaaaa\nbbbbbb bbbbb\n   \n";
String[] split = str.split("\n\\s*");
System.out.println(Arrays.toString(split));

Output:

[aaaaaaaaa, bbbbbb bbbbb]

Answer 2

This should do the trick:

String str="aaaaaaaaa\n\n\nbbbbbbbbbbb\n   \n";
String[] lines = str.split("\\s*\n\\s*");

It will also remove all trailing and leading whitespace from all lines.

Answer 3

\\ ns被您的第一条语句删除：\\ s匹配\\ n