[英]How to submit form data to php using Twitter Bootstrap Wizard
I'm using http://vadimg.com/twitter-bootstrap-wizard-example/#docs and I am having difficulty finding how to submit the data to the backend php script. 我正在使用http://vadimg.com/twitter-bootstrap-wizard-example/#docs ,但是我很难找到如何将数据提交到后端php脚本。
Once I have initialised the Wizard I have tried to add into the options being passed to the method a submitURL (I read somewhere it could be set as var wizard = $("#some-wizard").wizard({submitUrl: "/some_url"});
初始化向导后,我尝试将传递URL的选项添加到一个SubmitURL(我在某处读取,可以将其设置为
var wizard = $("#some-wizard").wizard({submitUrl: "/some_url"});
I have also tried the following : 我也尝试了以下方法:
var wizard = FormWizard.init();
$('#form_wizard_1 .button-submit').click(function (wizard) {
$.ajax({
url: "local_tmf_setup.php",
type: "POST",
data: wizard.serialize(),
success:function(){
alert('success.');
}
});
}).hide();
But it fails on the serialize method. 但是它在序列化方法上失败。
I've also looked at the documentation here: https://github.com/VinceG/twitter-bootstrap-wizard to see if there is an onSubmit event that the options could be passed to, but it appears the only event is onLast which I have tried as well. 我也在这里查看了文档: https : //github.com/VinceG/twitter-bootstrap-wizard ,看看是否存在可以将选项传递给onSubmit事件,但看来唯一的事件是onLast我也尝试过。
Any ideas? 有任何想法吗?
My wizard contains information stored in a knockoutJS view model, so I just write it to the backend using a normal ajax / JSON call. 我的向导包含存储在淘汰表视图模型中的信息,因此我只是使用常规的ajax / JSON调用将其写入后端。 Would that be an idea?
那是个主意吗? I was not aware that the wizard even had a submit parameter.
我不知道该向导甚至有一个Submit参数。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.