使用strcpy函数时的缓冲区溢出

Question

I'm trying to use strcpy in order to put a string in an array of strings. This is my definiton of the arrays:

char movies[10][150], movie[150];
int i = 0, j = 0;

currentChar = getchar();

while(currentChar != EOF)
{
    while(currentChar!='\n')
    {
        movie[i] = currentChar;
        currentChar = getchar();
        i++;
    }

    strcpy(*(movies + j*10*15), (char*)movie);
    j++;
    currentChar = getchar();
}

Trying to debug it in c++ console, I get a 'Buffer is too small' message.

note: My input is "Django unshaved:a bit bloody, but overall a solid film" which does not exceed the 150 chars.

thanks for helping.

edit: code edited to show full picture

Answer 1

You should use this code instead:

strcpy(movies[j], movie);

IMHO, it doesn't make sense to define a two-dimensional array and then use it as if it was one large one-dimensional array defined as char[1500].

Also, which compiler are you using that generates such a message for C -code?

Answer 2

您的复制函数调用应为：

strcpy((movies + j*150), (char*)movie);

Answer 3

Finally I solved the problem. Apparently, in the end of 'movie' there wasn't a '\\n' character and strcpy could not handle it.

Adding a '\\n' at the end of the string solves the problem.