[英]How to fully suppress an error when invoking powershell with a command?
I'm trying to write an msbuild postbuild event that will copy a file. 我正在尝试编写msbuild postbuild事件,该事件将复制文件。 It need not be 100% - the destination file might be used or locked in which case I would like the build to succeed.
它不必是100%-目标文件可以使用或锁定,在这种情况下,我希望构建成功。
so I have something like* 所以我有类似*的东西
PowerShell -NoProfile -ExecutionPolicy Bypass -Command "cp foo `$(TargetDir)"
when $(TargetDir)\\foo
is used by another process I get an error and my build fails. 当
$(TargetDir)\\foo
被另一个进程使用时,出现错误,构建失败。 So I try 所以我尝试
PowerShell -NoProfile -ExecutionPolicy Bypass -Command "cp foo `$(TargetDir) -ErrorAction SilentlyContinue"
yet the error is printed and it fails. 但错误已打印且失败。 So I try
所以我尝试
PowerShell -NoProfile -ExecutionPolicy Bypass -Command "try { cp foo `$(TargetDir) } catch {}"
and now the error is not printed yet it STILL fails because if I execute the above $LastExitCode
still equals 1. 现在错误没有被打印出来,但是它仍然失败,因为如果我执行上面的
$LastExitCode
仍然等于1。
I can wrap yet again in try catch and powershell but how do I suppress the error correctly? 我可以在try catch和powershell中再次包装,但是如何正确抑制错误?
*The actual command is the following - not that it matters *实际的命令如下-没关系
PowerShell -NoProfile -ExecutionPolicy Bypass -Command `"try { ls '`$(SolutionDir)\packages\GhostScriptSharp.*\Tools\gsdll32.dll' | Sort -Descending | Select -First 1 | cp -Destination '`$(TargetDir)' } catch {}`""
您可以使用exit
关键字来显式设置脚本的退出代码:
PowerShell -NoProfile -ExecutionPolicy Bypass -Command "cp foo `$(TargetDir) -ErrorAction SilentlyContinue; exit 0"
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